(Figure 1) shows a proton that, at this instant, is moving the +x-direction through a regionin which there is a uniform 1.41 x 106 V/m electric field and a uniform 1.41 T magneticfield, each at a 45° angle from the +x-axis. We want to understand the force on the protonin the laboratory reference frame and also in the proton's reference frame.Show Transcribed TextPart CWhat is the electric field in frame B, in component form?Express your answer in terms of the units vectors (î, and k), in volts per meter.► View Available Hint(s)ĒB =Figure15. ΑΣΦxaXbA(i+j + okShow Transcribed Text1.41×106 V/m45°450.√x vx1.41 T6ĴSundoYou have already submitted this answer. Enter a new answer.No credit lost. Try again.|X|ĒLX.10nXv=1.0x10 m/sLaboratoryframe?X<V/m1 of 1

Answered: Image /qna-images/answer/7708d749-c9dd-44e1-9b8e-a9e2b1b34905.jpg

(Figure 1) shows a proton that, at this instant, is moving the +x-direction through a region in which there is a uniform 1.41 x 106 V/m electric field and a uniform 1.41 T magnetic field, each at a 45° angle from the +x-axis. We want to understand the force on the proton in the laboratory reference frame and also in the proton's reference frame. Show Transcribed Text Part C G C

(Figure 1) shows a proton that, at this instant, is moving the +x-direction through a region in which there is a uniform 1.41 x 106 V/m electric field and a uniform 1.41 T magnetic field, each at a 45° angle from the +x-axis. We want to understand the force on the proton in the laboratory reference frame and also in the proton's reference frame. Show Transcribed Text Part C G C