Fawns between 1 and 5 months old have a body weight that is approximately normally distributed with mean ? = 28.6 kilograms and standard deviation ? = 3.1 kilograms. Let x be the weight of a fawn in kilograms. Convert the following x intervals to z intervals. (Round your answers to two decimal places.) (a) x < 30 z < (b) 19 < x < z (c) 32 < x < 35 < z< Convert the following z intervals to x
Fawns between 1 and 5 months old have a body weight that is approximately normally distributed with mean ? = 28.6 kilograms and standard deviation ? = 3.1 kilograms. Let x be the weight of a fawn in kilograms. Convert the following x intervals to z intervals. (Round your answers to two decimal places.) (a) x < 30 z < (b) 19 < x < z (c) 32 < x < 35 < z< Convert the following z intervals to x
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
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Problem 1P
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Fawns between 1 and 5 months old have a body weight that is approximately normally distributed with mean ? = 28.6 kilograms and standard deviation ? = 3.1 kilograms. Let x be the weight of a fawn in kilograms.
Convert the following x intervals to z intervals. (Round your answers to two decimal places.)
Convert the following z intervals to x intervals. (Round your answers to one decimal place.)
(a) x < 30
z <
(b) 19 < x
< z
(c) 32 < x < 35
< z<
z <
(b) 19 < x
< z
(c) 32 < x < 35
< z<
Convert the following z intervals to x intervals. (Round your answers to one decimal place.)
(d) −2.17 < z
< x
(e) z < 1.28
x <
(f) −1.99 < z < 1.44
< x <
(g) If a fawn weighs 14 kilograms, would you say it is an unusually small animal? Explain using z values and the figure above.
(h) If a fawn is unusually large, would you say that the z value for the weight of the fawn will be close to 0, −2, or 3? Explain.
< x
(e) z < 1.28
x <
(f) −1.99 < z < 1.44
< x <
(g) If a fawn weighs 14 kilograms, would you say it is an unusually small animal? Explain using z values and the figure above.
Yes. This weight is 4.71 standard deviations below the mean; 14 kg is an unusually low weight for a fawn.Yes. This weight is 2.35 standard deviations below the mean; 14 kg is an unusually low weight for a fawn. No. This weight is 4.71 standard deviations below the mean; 14 kg is a normal weight for a fawn.No. This weight is 4.71 standard deviations above the mean; 14 kg is an unusually high weight for a fawn.No. This weight is 2.35 standard deviations above the mean; 14 kg is an unusually high weight for a fawn.
(h) If a fawn is unusually large, would you say that the z value for the weight of the fawn will be close to 0, −2, or 3? Explain.
It would have a large positive z, such as 3.It would have a negative z, such as −2. It would have a z of 0.
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