Fawns between 1 and 5 months old have a body weight that is approximately normally distributed with mean ? = 28.6 kilograms and standard deviation ? = 3.1 kilograms. Let x be the weight of a fawn in kilograms.   Convert the following x intervals to z intervals. (Round your answers to two decimal places.) (a)    x < 30 z < (b)    19 < x < z (c)    32 < x < 35 < z< Convert the following z intervals to x

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Fawns between 1 and 5 months old have a body weight that is approximately normally distributed with mean ? = 28.6 kilograms and standard deviation ? = 3.1 kilograms. Let x be the weight of a fawn in kilograms.
 
Convert the following x intervals to z intervals. (Round your answers to two decimal places.)
(a)    x < 30
z <

(b)    19 < x
< z

(c)    32 < x < 35
< z<

Convert the following z intervals to x intervals. (Round your answers to one decimal place.)
(d)    −2.17 < z
< x

(e)    z < 1.28
x <

(f)    −1.99 < z < 1.44
< x <
(g) If a fawn weighs 14 kilograms, would you say it is an unusually small animal? Explain using z values and the figure above.
Yes. This weight is 4.71 standard deviations below the mean; 14 kg is an unusually low weight for a fawn.Yes. This weight is 2.35 standard deviations below the mean; 14 kg is an unusually low weight for a fawn.     No. This weight is 4.71 standard deviations below the mean; 14 kg is a normal weight for a fawn.No. This weight is 4.71 standard deviations above the mean; 14 kg is an unusually high weight for a fawn.No. This weight is 2.35 standard deviations above the mean; 14 kg is an unusually high weight for a fawn.

(h) If a fawn is unusually large, would you say that the z value for the weight of the fawn will be close to 0, −2, or 3? Explain.
It would have a large positive z, such as 3.It would have a negative z, such as −2.     It would have a z of 0.
 
 

 

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