Fawns between 1 and 5 months old have a body weight that is approximately normally distributed with mean ? = 29.4 kilograms and standard deviation ? = 4.4 kilograms. Let x be the weight of a fawn in kilograms. Convert the following x intervals to z intervals. (Round your answers to two decimal places.) (a) x < 30 z < ___ (b) 19 < x ______< z (c) 32 < x < 35 ____< z < ____
Fawns between 1 and 5 months old have a body weight that is approximately normally distributed with mean ? = 29.4 kilograms and standard deviation ? = 4.4 kilograms. Let x be the weight of a fawn in kilograms. Convert the following x intervals to z intervals. (Round your answers to two decimal places.) (a) x < 30 z < ___ (b) 19 < x ______< z (c) 32 < x < 35 ____< z < ____
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Fawns between 1 and 5 months old have a body weight that is approximately
Convert the following x intervals to z intervals. (Round your answers to two decimal places.)
(a) x < 30
z < ___
(b) 19 < x
______< z
(c) 32 < x < 35
____< z < ____
Convert the following z intervals to x intervals. (Round your answers to one decimal place.)
(d) −2.17 < z
_____ < x
(e) z < 1.28
x < ______
(f) −1.99 < z < 1.44
______< x < ______
(g) If a fawn weighs 14 kilograms, would you say it is an unusually small animal? Explain using z values and the figure above.
_____ < x
(e) z < 1.28
x < ______
(f) −1.99 < z < 1.44
______< x < ______
(g) If a fawn weighs 14 kilograms, would you say it is an unusually small animal? Explain using z values and the figure above.
A-Yes. This weight is 3.50 standard deviations below the mean; 14 kg is an unusually low weight for a fawn.
B-Yes. This weight is 1.75 standard deviations below the mean; 14 kg is an unusually low weight for a fawn.
C-No. This weight is 3.50 standard deviations below the mean; 14 kg is a normal weight for a fawn.
D-No. This weight is 3.50 standard deviations above the mean; 14 kg is an unusually high weight for a fawn.No. This weight is 1.75 standard deviations above the mean; 14 kg is an unusually high weight for a fawn.
(h) If a fawn is unusually large, would you say that the z value for the weight of the fawn will be close to 0, −2, or 3? Explain.
A-It would have a z of 0.
B-It would have a large positive z, such as 3.
C-It would have a negative z, such as −2.
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