Fair stain O removal Very good Good The table to the right shows the cost per ounce (in dollars) for a random sample of toothpastes exhibiting very good stain removal, good stain removal, and fair stain removal At a = 0.05, can you conclude that the mean costs per ounce are different? Perform a one-way ANOVA test by completing parts a through d. Assume that each sample is drawn from a normal population, that the samples are independent of each other, and that the populations have the same variances. stain removal stain removal 0.35 0.64 0.64 0.60 2.66 1.32 0.36 0.98 0.44 1.59 0.58 0.37 0.33 0.47 1.39 (a) Identify the claim and state Ho and H. Choose the correct answer below. B. Ho: H = 2 =H3 O A. Ho: H1 =2 "H3 "Ha Hs "H6 H: At least two means are different from the others. (claim) H: At least one mean is different from the others. (claim) O D. Ho: At least one mean is different from the others. (daim) OC. Ho: H =H2 =H3 (claim) H: H1 = H2 = H3 "H4 "Hs "H6 H: At least one mean is different from the others. (b) Identify the degrees of freedom for the numerator and for the denominator, determine the critical value, and determine the cejection region. The degrees of freedom for the numerator, d.f.N, is 2, and the degrees of freedom for the denominator, d.f.p. is 12. The critical value is Fo= 3.89 (Round to two decimal places as needed.) The rejection region is F > 3.89 (Round to two decimal places as needed.) (c) Calculate the test statistic. F= (Round to three decimal places as needed.)
Fair stain O removal Very good Good The table to the right shows the cost per ounce (in dollars) for a random sample of toothpastes exhibiting very good stain removal, good stain removal, and fair stain removal At a = 0.05, can you conclude that the mean costs per ounce are different? Perform a one-way ANOVA test by completing parts a through d. Assume that each sample is drawn from a normal population, that the samples are independent of each other, and that the populations have the same variances. stain removal stain removal 0.35 0.64 0.64 0.60 2.66 1.32 0.36 0.98 0.44 1.59 0.58 0.37 0.33 0.47 1.39 (a) Identify the claim and state Ho and H. Choose the correct answer below. B. Ho: H = 2 =H3 O A. Ho: H1 =2 "H3 "Ha Hs "H6 H: At least two means are different from the others. (claim) H: At least one mean is different from the others. (claim) O D. Ho: At least one mean is different from the others. (daim) OC. Ho: H =H2 =H3 (claim) H: H1 = H2 = H3 "H4 "Hs "H6 H: At least one mean is different from the others. (b) Identify the degrees of freedom for the numerator and for the denominator, determine the critical value, and determine the cejection region. The degrees of freedom for the numerator, d.f.N, is 2, and the degrees of freedom for the denominator, d.f.p. is 12. The critical value is Fo= 3.89 (Round to two decimal places as needed.) The rejection region is F > 3.89 (Round to two decimal places as needed.) (c) Calculate the test statistic. F= (Round to three decimal places as needed.)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
(c) Calculate the test statistic.
![Very good
Good
Fair stain e
The table to the right shows the cost per ounce (in dollars) for a random sample of toothpastes exhibiting very good stain removal, good stain removal, and fair stain removal.
At a= 0.05, can you conclude that the mean costs per ounce are different? Perform a one-way ANOVA test by completing parts a through d. Assume that each sample is drawn
from a normal population, that the samples are independent of each other, and that the populations have the same variances.
removal
stain
removal
0.35
stain
removal
0.60
1.32
0.64
0.64
2.66
0.36
0.98
0.44
0.58
1.59
0.37
0.47
0.33
1.39
(a) Identify the claim and state Ho and H. Choose the correct answer below.
B. Ho: H = H2 =H3
O A. Ho: H1 =H2 =H3 "Ha "Hs " He
H: At least one mean is different from the others. (claim)
H: At least two means are different from the others. (claim)
O D. Ho: At least one mean is different from the others. (claim)
OC. Ho: H " H2 =H3 (claim)
H: At least one mean is different from the others.
(b) Identify the degrees of freedom for the numerator and for the denominator, determine the critical value, and determine the tejection region.
The degrees of freedom for the numerator, d.f.N, is 2, and the degrees of freedom for the denominator, d.f.p. is 12.
The critical value is Fo= 3.89
(Round to two decimal places as needed.
The rejection region is F > 3.89
(Round to two decimal places as needed.)
(c) Calculate the test statistic.
(Round to three decimal places as needed.)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb3e2ca0c-118c-4247-9870-a80452c2e296%2F9f1fc45e-ee24-447e-af8a-b0c0d6b6ac9a%2Fb8x7x5u_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Very good
Good
Fair stain e
The table to the right shows the cost per ounce (in dollars) for a random sample of toothpastes exhibiting very good stain removal, good stain removal, and fair stain removal.
At a= 0.05, can you conclude that the mean costs per ounce are different? Perform a one-way ANOVA test by completing parts a through d. Assume that each sample is drawn
from a normal population, that the samples are independent of each other, and that the populations have the same variances.
removal
stain
removal
0.35
stain
removal
0.60
1.32
0.64
0.64
2.66
0.36
0.98
0.44
0.58
1.59
0.37
0.47
0.33
1.39
(a) Identify the claim and state Ho and H. Choose the correct answer below.
B. Ho: H = H2 =H3
O A. Ho: H1 =H2 =H3 "Ha "Hs " He
H: At least one mean is different from the others. (claim)
H: At least two means are different from the others. (claim)
O D. Ho: At least one mean is different from the others. (claim)
OC. Ho: H " H2 =H3 (claim)
H: At least one mean is different from the others.
(b) Identify the degrees of freedom for the numerator and for the denominator, determine the critical value, and determine the tejection region.
The degrees of freedom for the numerator, d.f.N, is 2, and the degrees of freedom for the denominator, d.f.p. is 12.
The critical value is Fo= 3.89
(Round to two decimal places as needed.
The rejection region is F > 3.89
(Round to two decimal places as needed.)
(c) Calculate the test statistic.
(Round to three decimal places as needed.)
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