F8-14. A solid circular rod that is 600 mm long and 20 mmin diameter is subjected to an axial force of P- 50 kN. Theelongation of the rod is 8 - 1.40 mm, and its diameterbecomes d' - 19.9837 mm. Determine the modulus ofelasticity and the modulus of rigidity of the material.Assume that the material does not yield.P= 50 kN600 mm20 mmP= 50 kN

Given data as per question length of rod = 600 mm Diameter of shaft =20mm Final diameter =…

Answered: F8-14. A solid circular rod that is 600…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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The d = 17-mm-diameter solid rod passes through a D = 22-mm-diameter hole in the support plate. When a load P is applied to the rod, the rod head rests on the support plate. The support plate has a thickness of b = 12 mm. The rod head has a diameter of a = 34 mm, and the head has a thickness of t = 9 mm. The shear stress in the rod head cannot exceed 125 MPa, the punching shear stress in the support plate cannot exceed 80 MPa, and the bearing stress between the rod head and the support plate cannot exceed 120 MPa. Determine the maximum value of Pmax that can be supported by the structure.
The two bars are used to support load P. When unloaded, joint B has coordinates (0, 0). After load P is applied, joint B moves to the coordinate position (-0.47 in., -0.16 in.). Assume a - 17 ft, b-34 ft, c-12 ft, and d - 24 ft. Determine the normal strain in each bar. Answer: EAB- T EBC i P a e (1) B UE με b (2) C d
SN = 79 kips
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*3-12. Fiberglass has a stress-strain diagram as shown. If a 50-mm-diameter bar of length 2 m made from this material is subjected to an axial tensile load of 60 kN, determine its elongation. σ (Pa) 300(10%) 1/2 €(mm/mm)
The 200 mm long and 20 mm diameter solid circular rod is subjected to an axial force of P. P = 400 and δ = 1.6. ElasticityCalculate the modulus E and the shear modulus G. Take 0.3 Poisson's ratio.
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Can someone please explain the step-by-step process of this. Thank you so much! The d = 12-mm-diameter solid rod passes through a D = 17-mm-diameter hole in the support plate. When a load P is applied to the rod, the rod head rests on the support plate. The support plate has a thickness of b = 13 mm. The rod head has a diameter of a = 24 mm, and the head has a thickness of t = 9 mm. The shear stress in the rod head cannot exceed 130 MPa, the punching shear stress in the support plate cannot exceed 85 MPa, and the bearing stress between the rod head and the support plate cannot exceed 130 MPa. Determine the maximum value of Pmax that can be supported by the structure.
The d - 15-mm-diameter solid rod passes through a D=20-mm-diameter hole in the support plate. When a load P is applied to the rod, the rod head rests on the support plate. The support plate has a thickness of b- 13 mm. The rod head has a diameter of a = 30 mm, and the head has a thickness of t= 10 mm. The shear stress in the rod head cannot exceed 130 MPa, the punching shear stress in the support plate cannot exceed 90 MPa, and the bearing stress between the rod head and the support plate cannot exceed 140 MPa. Determine the maximum value of Pmax that can be supported by the structure. Support Plate Rod Answer: Pmax i -Hole diameter D Head kN ام

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