The shear stress-strain diagram for an alloy is shown in the figure. If a bolt having a diameter of 0.25 in. is made of this material and used in the lap joint, determine the modulus of elasticity E and the force P required to cause the material to yield. Take p = 0.3. 7 (ksi) Ty=50 P 0.004 y (rad)
The shear stress-strain diagram for an alloy is shown in the figure. If a bolt having a diameter of 0.25 in. is made of this material and used in the lap joint, determine the modulus of elasticity E and the force P required to cause the material to yield. Take p = 0.3. 7 (ksi) Ty=50 P 0.004 y (rad)
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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![**Problem 7**
The shear stress-strain diagram for an alloy is shown in the figure. If a bolt having a diameter of 0.25 in. is made of this material and used in the lap joint, determine the modulus of elasticity \( E \) and the force \( P \) required to cause the material to yield. Take \(\nu = 0.3\).
**Diagram Explanation:**
- The graph depicts a shear stress-strain curve.
- The vertical axis represents shear stress \(\tau\) in ksi (kips per square inch).
- The horizontal axis represents shear strain \(\gamma\) in radians.
- The yield shear stress \(\tau_Y\) is marked at 50 ksi.
- The stress-strain curve is linear up to a point (\(\gamma = 0.004\) radians), indicating the material's elastic behavior.
- Below the graph, there is a schematic of a bolt in a lap joint, with force \( P \) being applied in opposite directions on either side of the joint.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb3da0cd1-4491-4699-a531-553fdaf9ab08%2Fdb9538f2-e9fc-4008-83ad-106bc9b9e494%2Fwvrl3r9_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem 7**
The shear stress-strain diagram for an alloy is shown in the figure. If a bolt having a diameter of 0.25 in. is made of this material and used in the lap joint, determine the modulus of elasticity \( E \) and the force \( P \) required to cause the material to yield. Take \(\nu = 0.3\).
**Diagram Explanation:**
- The graph depicts a shear stress-strain curve.
- The vertical axis represents shear stress \(\tau\) in ksi (kips per square inch).
- The horizontal axis represents shear strain \(\gamma\) in radians.
- The yield shear stress \(\tau_Y\) is marked at 50 ksi.
- The stress-strain curve is linear up to a point (\(\gamma = 0.004\) radians), indicating the material's elastic behavior.
- Below the graph, there is a schematic of a bolt in a lap joint, with force \( P \) being applied in opposite directions on either side of the joint.
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