F7-22. The pin is made of a material having a failure shearstress of Ta - 100 MPa. Determine the minimum requireddiameter of the pin to the nearest mm. Apply a factor ofsafety of F.S. - 2.5 against shear failure.s0 kN

Given: The magnitude of the force is P=80 kN. The factor of safety is F.S=2.5. The shear stress due…

Answered: F7-22. The pin is made of a material…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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A pull of 6,500 lb is applied to a steel rod which has an ultimate stress of 65,000 psi. Determine the steel rod diameter if the factor of safety is 5. A. 0.998 inch B. 0.598 inch C. 0.798 inch D. 0.398 inch
Two steel plates are held together by two bolts. (/6) a. Determine the required diameter of the bolts if the failure shear stress is 300 MPa using a Factor of Safety (FS) of 2. b. Using the answer from a. above, determine the steel plate thickness if the failure bearing stress of the steel is 350 MPa using FS = 1.5. Show your work. OKN Two Bolts P=60KN
If a critical point at structural element is subjected to the stress shown on the 2D element, determine the factor of safety (FS) against rupture according to the maximum principal stress theory. The material has an ultimate tensile stress Sult = 400 Mpa. 100 Мра 80 Мра 150 Mpa
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Question 5 of 5 View Policies Current Attempt in Progress For the connection shown, determine the average shear stress in the 0.75-in.-diameter bolts if the load is P = 60 kips. O 27.2 ksi O 37.5 ksi O 25.8 ksi O 21.9 ksi O 35.3 ksi
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• Bars (1) have a cross-sectional area of A₁ = 0.65 in.2 and a length, L₁= 7 ft. • Bars (1) are made of cast iron with an elastic modulus of E₁ = 24,000 ksi, a coefficient of thermal expansion, a₁ = 12.3 x 10-6/°F and yield strength of oy = 120 ksi. • Bar (2) has a cross-sectional area of A₂ = 1.45 in.² and a length, L₂ = 5.5 ft. • Bar (2) is made of stainless steel with a coefficient of thermal expansion, a₂ = 10.6 × 10-6/°F. • The stress-strain diagram provided below presents the results of the stainless steel's (i.e., Bar (2)) bar tension test. • There is a gap of A = 0.1 in. in the connection at B and a = 3 ft. • All bars are unstressed before a load P = 12 kips is applied and the temperature increases by AT = 40°F. Stress-strain diagram for stainless steel bar: (1) a Stress (ksi) L2 Rigid bar 120 100 80 60 40 20 0 0 0 B (2) P a (1) C Upper scale L₁ Connection details at node C Lower scale. C 0.025 0.050 0.075 0.100 0.125 0.150 0.175 0.006 0.008 0.010 0.012 0.014 0.002 0.004 Strain…
Part A -80 mm- P 75 mm -40 mm 30 mm If the bolt head and the supporting bracket are made of the same material having a failure shear stress of Tfail = 150 MPa, determine the maximum allowable force P that can be applied to the bolt so that it does not pull through the support. Apply a factor of safety of F.S. = 2.5 against shear failure. Express your answer to three significant figures and include the appropriate units.
FBD 3. Determine the required thickness of member BC and the diameter of the pins at A and B if the failure normal stress for member BC is Ofail = 30 ksi, and the failure shear stress for the pins is Tfail = 12 ksi. Use a safety factor of 1.2 to your design. Solution: 1.5 in. 60° 8 ft 5 kip/ft
An axial load is applied to the rectangular cross section bar which is welded at the 57 degree angle shown. If the weld material has a failure normal stress of 160 mPa and a failure shear stress of 90 mPa, determine the required thickness if a factor of safety of 2.3 is required. Also determine the required diameter of the bolts(to the nearest mm) if the plate is face bolted to the supports. The bolt material has a failure shear stress of 175 mPa.
Determine the minimum required failure shear stress "T" for the material used for a pin with a diameter of 20 mm, so it can support the applied load. Apply a factor of safety of F.S. = 1.8 against shear failure. 80 kN

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F7-22. The pin is made of a material having a failure shear stress of Ta - 100 MPa. Determine the minimum required diameter of the pin to the nearest mm. Apply a factor of safety of F.S. - 2.5 against shear failure. s0 kN