F2 30.0 JF1 K 2.00 m *3.00m->l Find the net (or total) torque about point O for the two forces as in the figure above. let F1 = 7.80N and Fa=15. ON. Express your answer in newton-meters.

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### Understanding Torque and its Calculation

In the following exercise, we will learn how to find the net (or total) torque about a point due to multiple forces acting on a lever. 

#### Problem Statement:
Find the net (or total) torque about point \( O \) for the two forces as depicted in the figure. Let \( F_1 = 7.80 \) N and \( F_2 = 15.0 \) N. Express your answer in Newton-meters.

#### Description of the Diagram:
- The diagram shows a horizontal lever (or rod) balanced on a pivot point, labeled as point \( O \).
- Two forces, \( F_1 \) and \( F_2 \), are acting on the lever.
- Force \( F_1 \) is acting downwards at a point 3.00 meters to the right of \( O \).
- Force \( F_2 \) is acting at an angle of 30.0° upwards to the left at a point 2.00 meters from \( O \).

#### Calculations for Torque:
Torque (\( \tau \)) is calculated using the formula:
\[ \tau = r \cdot F \cdot \sin(\theta) \]

Where:
- \( r \) is the distance from the pivot point to the point where the force is applied.
- \( F \) is the magnitude of the force applied.
- \( \theta \) is the angle between the force and the lever arm.

#### Step-by-Step Calculation:

1. **Torque due to \( F_1 \):**
   \[
   \tau_1 = r_1 \cdot F_1 \cdot \sin(90^\circ) 
   \]
   Since \( \sin(90^\circ) = 1 \) and \( r_1 = 3.00 \) m,
   \[
   \tau_1 = 3.00 \, \text{m} \cdot 7.80 \, \text{N} \cdot 1 = 23.4 \, \text{Nm}
   \]
   (Positive direction, assuming counterclockwise)

2. **Torque due to \( F_2 \):**
   \[
   \tau_2 = r_2 \cdot F_2 \cdot \sin(30^\circ) 
   \]
   Since
Transcribed Image Text:### Understanding Torque and its Calculation In the following exercise, we will learn how to find the net (or total) torque about a point due to multiple forces acting on a lever. #### Problem Statement: Find the net (or total) torque about point \( O \) for the two forces as depicted in the figure. Let \( F_1 = 7.80 \) N and \( F_2 = 15.0 \) N. Express your answer in Newton-meters. #### Description of the Diagram: - The diagram shows a horizontal lever (or rod) balanced on a pivot point, labeled as point \( O \). - Two forces, \( F_1 \) and \( F_2 \), are acting on the lever. - Force \( F_1 \) is acting downwards at a point 3.00 meters to the right of \( O \). - Force \( F_2 \) is acting at an angle of 30.0° upwards to the left at a point 2.00 meters from \( O \). #### Calculations for Torque: Torque (\( \tau \)) is calculated using the formula: \[ \tau = r \cdot F \cdot \sin(\theta) \] Where: - \( r \) is the distance from the pivot point to the point where the force is applied. - \( F \) is the magnitude of the force applied. - \( \theta \) is the angle between the force and the lever arm. #### Step-by-Step Calculation: 1. **Torque due to \( F_1 \):** \[ \tau_1 = r_1 \cdot F_1 \cdot \sin(90^\circ) \] Since \( \sin(90^\circ) = 1 \) and \( r_1 = 3.00 \) m, \[ \tau_1 = 3.00 \, \text{m} \cdot 7.80 \, \text{N} \cdot 1 = 23.4 \, \text{Nm} \] (Positive direction, assuming counterclockwise) 2. **Torque due to \( F_2 \):** \[ \tau_2 = r_2 \cdot F_2 \cdot \sin(30^\circ) \] Since
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