F2 30.0 JF1 K 2.00 m *3.00m->l Find the net (or total) torque about point O for the two forces as in the figure above. let F1 = 7.80N and Fa=15. ON. Express your answer in newton-meters.
F2 30.0 JF1 K 2.00 m *3.00m->l Find the net (or total) torque about point O for the two forces as in the figure above. let F1 = 7.80N and Fa=15. ON. Express your answer in newton-meters.
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![### Understanding Torque and its Calculation
In the following exercise, we will learn how to find the net (or total) torque about a point due to multiple forces acting on a lever.
#### Problem Statement:
Find the net (or total) torque about point \( O \) for the two forces as depicted in the figure. Let \( F_1 = 7.80 \) N and \( F_2 = 15.0 \) N. Express your answer in Newton-meters.
#### Description of the Diagram:
- The diagram shows a horizontal lever (or rod) balanced on a pivot point, labeled as point \( O \).
- Two forces, \( F_1 \) and \( F_2 \), are acting on the lever.
- Force \( F_1 \) is acting downwards at a point 3.00 meters to the right of \( O \).
- Force \( F_2 \) is acting at an angle of 30.0° upwards to the left at a point 2.00 meters from \( O \).
#### Calculations for Torque:
Torque (\( \tau \)) is calculated using the formula:
\[ \tau = r \cdot F \cdot \sin(\theta) \]
Where:
- \( r \) is the distance from the pivot point to the point where the force is applied.
- \( F \) is the magnitude of the force applied.
- \( \theta \) is the angle between the force and the lever arm.
#### Step-by-Step Calculation:
1. **Torque due to \( F_1 \):**
\[
\tau_1 = r_1 \cdot F_1 \cdot \sin(90^\circ)
\]
Since \( \sin(90^\circ) = 1 \) and \( r_1 = 3.00 \) m,
\[
\tau_1 = 3.00 \, \text{m} \cdot 7.80 \, \text{N} \cdot 1 = 23.4 \, \text{Nm}
\]
(Positive direction, assuming counterclockwise)
2. **Torque due to \( F_2 \):**
\[
\tau_2 = r_2 \cdot F_2 \cdot \sin(30^\circ)
\]
Since](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa49c042c-e715-46d7-b1af-568fb3890c2a%2Fc00868ee-a5dc-4a4d-8a74-7ac6af37e8cc%2Fseuk58o_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Understanding Torque and its Calculation
In the following exercise, we will learn how to find the net (or total) torque about a point due to multiple forces acting on a lever.
#### Problem Statement:
Find the net (or total) torque about point \( O \) for the two forces as depicted in the figure. Let \( F_1 = 7.80 \) N and \( F_2 = 15.0 \) N. Express your answer in Newton-meters.
#### Description of the Diagram:
- The diagram shows a horizontal lever (or rod) balanced on a pivot point, labeled as point \( O \).
- Two forces, \( F_1 \) and \( F_2 \), are acting on the lever.
- Force \( F_1 \) is acting downwards at a point 3.00 meters to the right of \( O \).
- Force \( F_2 \) is acting at an angle of 30.0° upwards to the left at a point 2.00 meters from \( O \).
#### Calculations for Torque:
Torque (\( \tau \)) is calculated using the formula:
\[ \tau = r \cdot F \cdot \sin(\theta) \]
Where:
- \( r \) is the distance from the pivot point to the point where the force is applied.
- \( F \) is the magnitude of the force applied.
- \( \theta \) is the angle between the force and the lever arm.
#### Step-by-Step Calculation:
1. **Torque due to \( F_1 \):**
\[
\tau_1 = r_1 \cdot F_1 \cdot \sin(90^\circ)
\]
Since \( \sin(90^\circ) = 1 \) and \( r_1 = 3.00 \) m,
\[
\tau_1 = 3.00 \, \text{m} \cdot 7.80 \, \text{N} \cdot 1 = 23.4 \, \text{Nm}
\]
(Positive direction, assuming counterclockwise)
2. **Torque due to \( F_2 \):**
\[
\tau_2 = r_2 \cdot F_2 \cdot \sin(30^\circ)
\]
Since
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