What is the torque about the pivot point shown by the 8.00 N force, in N-m? (Pay attention to the sign.) Your answer needs to have 2 significant figures, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer, it is already given in the question statement. 8.0 N 10 N 40 25 cm 75 cm 30°

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Chapter1: Units, Trigonometry. And Vectors
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**Question:**

What is the torque about the pivot point shown by the 8.00 N force, in N·m? (Pay attention to the sign.)

*Your answer needs to have 2 significant figures, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer, it is already given in the question statement.*

**Diagram Explanation:**

The diagram includes a horizontal rod of length 100 cm. 

- A pivot point is located at 25 cm from the left end of the rod.
- An 8.0 N force is applied at the left end, directed at an angle of 40° above the horizontal.
- A 10 N force is applied at the right end, directed at an angle of 30° above the horizontal.
- The distances from the pivot to the points where forces are applied are labeled as 25 cm (for the 8.0 N force) and 75 cm (for the 10 N force).
Transcribed Image Text:**Question:** What is the torque about the pivot point shown by the 8.00 N force, in N·m? (Pay attention to the sign.) *Your answer needs to have 2 significant figures, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer, it is already given in the question statement.* **Diagram Explanation:** The diagram includes a horizontal rod of length 100 cm. - A pivot point is located at 25 cm from the left end of the rod. - An 8.0 N force is applied at the left end, directed at an angle of 40° above the horizontal. - A 10 N force is applied at the right end, directed at an angle of 30° above the horizontal. - The distances from the pivot to the points where forces are applied are labeled as 25 cm (for the 8.0 N force) and 75 cm (for the 10 N force).
**Question:**

What is the net torque about the pivot point shown by the two given forces, in N·m? (Pay attention to the sign.)

*Your answer needs to have 2 significant figures, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer, it is already given in the question statement.*

**Diagram Explanation:**

- The diagram shows a horizontal bar with a pivot point on the left end.
- An 8.0 N force is applied at an angle of 40° to the left end, 25 cm from the pivot.
- A 10 N force is applied at an angle of 30° to the right end, 75 cm from the pivot.
- Both forces are directed upwards with arrows indicating their angles from the horizontal.

The problem requires calculating the net torque with respect to the pivot point using the forces and their respective distances and angles. Torque is determined by the equation: \( \tau = F \cdot d \cdot \sin(\theta) \), where:
- \( \tau \) is the torque,
- \( F \) is the magnitude of the force,
- \( d \) is the distance from the pivot,
- \( \theta \) is the angle between the force and the lever arm.
Transcribed Image Text:**Question:** What is the net torque about the pivot point shown by the two given forces, in N·m? (Pay attention to the sign.) *Your answer needs to have 2 significant figures, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer, it is already given in the question statement.* **Diagram Explanation:** - The diagram shows a horizontal bar with a pivot point on the left end. - An 8.0 N force is applied at an angle of 40° to the left end, 25 cm from the pivot. - A 10 N force is applied at an angle of 30° to the right end, 75 cm from the pivot. - Both forces are directed upwards with arrows indicating their angles from the horizontal. The problem requires calculating the net torque with respect to the pivot point using the forces and their respective distances and angles. Torque is determined by the equation: \( \tau = F \cdot d \cdot \sin(\theta) \), where: - \( \tau \) is the torque, - \( F \) is the magnitude of the force, - \( d \) is the distance from the pivot, - \( \theta \) is the angle between the force and the lever arm.
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