-F 200 N B D P |1000 mm 600 mm 800 mm 200 N- 800 mm: What is the couple moment of forces 200 N and -200 N ? O A) 160 j+ 120 k Nm B) 120 i- 180 k Nm C) 120 j+ 160 k Nm D) 120 i + 160 j Nm E) 120 i+ 160 k Nm

-F 200 N B D P |1000 mm 600 mm 800 mm 200 N- 800 mm: What is the couple moment of forces 200 N and -200 N ? O A) 160 j+ 120 k Nm B) 120 i- 180 k Nm C) 120 j+ 160 k Nm D) 120 i + 160 j Nm E) 120 i+ 160 k Nm

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Fl-5 KN F2 = 13 kN P- 60 F3 = 4 kN A 2 m F4 = 22 kN E a= 30 FS = 4 kN 1] What is the resultant moment of the five forces acting on the rod about point A? a) 11.1 kN.m b) 9.3 kN.m c) 16.2 kN.m ) 2.9 kN.m d) 18.5 kN.m e) 6.6 kN.m 2] What is the resultant moment of the five forces acting on the rod about point C? a) 65.1 kN.m b) 74.3 kN.m ) 19.2 kN.m d) 26.5 kN.m e) 42.9 kN.m H 55.1 kN.m 3] What is the moment of the force F1 about point E? a) – 19.3 kN.m b) -17.1 kN.m )- 6.3 kN.m d) - 22.1 kN.m e) - 39.7 kN.m )- 45.9 kN.m 4] What is the moment of the force F2 about point D? a) 17.1 kN.m c) 6.2 kN.m d) 14.5 kN.m ) 23.1 kN.m b) 48.3 kN.m e) 42.1 kN.m 5] What is the moment of the force F5 about point A? a) – 19.9 kN.m b) -18.1 kN.m e) - 8.3 kN.m d) - 15.1 kN.m e) - 2.7 kN.m f) - 6.8 kN.m
a.)The tension developed in wire CD. b.)The tension developed in wire BD. c.)The tension developed in wire AB. d.)The tension developed in wire BC
Given two vectors: The magnitude of 2N - M is: A) No Answer B) 6.08 C) 39.2 (D) 7.02 E 202 M = −3î +6ĵ- 5k and Ñ = -2î +3j + k
F3 = 800 N O A) 400 i -600 jN + 800 k Newton O B) 600 i-800j Newton F2 = 500 N %3D 370 C) 600 i+400j Newton D) 800 i+ 600j Newton y F1 = 1000 N F, is on the x-y plane. 1 E) 400 j+ 600 k Newton The angle between F3 and x axis is 135° , between F3 and y axis is 60°. Express force F, in vector form.
F1= 10 kN F2 = 26 kN B-45 45 F3 = 8 kN B. 4 m FA - 44 KN a-45° F5 = 8 kN 1] What is the resultant moment of the five forces acting on the rod about point A? a) 77.5 kN.m b) 108.1 kN.m ) 59.8 KN.m d) 153.1 kN.m e) 23.1 kN.m ) $6.4 kN.m 21 What is the resultant moment of the five forces acting on the rod about point C? e) 59.8 kN.m e) 99.1 kN.m n 86.4 kN.m a) 44.5 EN.m b) 187.1 kN.m d) 153.4 kN.m 31 What is the moment of the force F1 about point E? a) - 14.6 kN.m b) - 106.1 kN.m )- 48.8 kN.m d) - 215.8 kN.m ) - 99.7 kN.m )- 188.1 kN.m 4] What is the moment of the force F2 about point D? a) 19.5 kN.m b) 122.1 kN.m ) 88.8 kN.m d) 147.1 kN.m e) 58.1 kN.m ) 135.4 kN.m 5] What is the moment of the force F5 about point A? ) 44.8 kN.m a) 11.8 kN.m b) 5.7 KN.m d) 19.1 kN.m e) 69.4 kN.m ) 1.4 kN.m D.
8 kip 8 kip 3 B 3 C -10ft 7 ft - 4 ft→ Which of the following is closest to the magnitude of the moment about point C caused by the force couple shown? a) О b) 140 kip-ft c) 70.4 kip-ft d) 88.0 kip-ft
B kN = 4 B A kN 5 2 m C KN = 0 45 Ex E Ey 2 m 2 m Size and type of BF = CF 5) BF k N 6) cD 7) DE k N 8) DF
275 mm A) 100 N 30° 500 mm D O B) 50 N 500 mm B. O C) 300 N 300 mm u = friction coefficient on the crate surface (at A and at B) D) 400 N The system can hold the crate as shown in the figure. The system is in equilibrium. Ignore weight of the system. O E) 200 N The weight of the crate is 200 N. What is the value of P?
06: Determine the force in member JK. CJ and CD of the truss and indicate if the member in tension or compression. T 3 m L K B C 2 m2 m2 m - 2 m 4 KN 5 KN ען E 2 m 8 KN H F 2 m - 6 KN G
of gyal Ta-mr 160 2. What is the magnitude of moment Mp generated by force F=130 N if 0 = 35%, a = 280 mm and b = 60 mm? a) 34.3 Nm c) 25.3 Nm b) 29.8 Nm d) 27.3 Nm
F1 = 5 kN F2 = 13 kN 8 = 45° B = 60° C. F3 = 4 kN A 2 m 7 m D F4 = 22 kN El a = 30° F5 = 4 kN 1] What is the resultant moment of the five forces acting on the rod about point B? a) 31.5 kN.m b) 12.3 kN.m c) 26.2 kN.m d) 18.5 kN.m e) 32.1 kN.m f) 23.1 kN.m 2] What is the resultant moment of the five forces acting on the rod about point E? a) – 11.3 kN.m b) -26.4 kN.m c) - 6.9 kN.m d) - 32.1 kN.m e) - 30.7 kN.m f) - 15.9 kN.m 3] What is the moment of the force F1 about point D? a) – 35.4 kN.m b) -39.4 kN.m c) - 41.9 kN.m d) - 12.1 kN.m e) - 26.7 kN.m f) - 18.9 kN.m 4] What is the moment of the force F2 about point E? a) 47.5 kN.m b) 61.5 kN.m c) 22.2 kN.m d) 69.5 kN.m e) 77.1 kN.m f) 36.1 kN.m Activate Windows 5] What is the moment of the force F5 about point B? Go to Settings to activate Wir a) – 16.8 kN.m b) -11.4 kN.m c) – 25.9 kN.m d) - 9.1 kN.m e) - 1.7 kN.m f) - 25.9 kN.m
20. A rope 4.0 m long is coiled around the axle of a wheel whose combined moment of inertia is 6 kg-m. The rope is pulled with a constant force of 50 N. With what angular speed does the wheel rotating when the rope leaves the axle? Assume the wheel and axle initially at rest and the rope does not slip. wheel axle → 50 N A) 8.55 rad/s B) 8.16 rad/s C) 9.41 rad/s D) 8.99 rad/s