F, = 1.47 @ o° Fz= 1.96 @ 90° @ 90° Frel.9 F=1.47

Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter3: Vectors
Section: Chapter Questions
Problem 65PQ
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How do you solve for Resultant given this information. I was able to do the graphical method but I am unsure how n how to use the component method.
### Vector Addition

**Given Vectors:**
- \( F_1 = 1.47 \, \text{units} \) at \( 0^\circ \)
- \( F_2 = 1.96 \, \text{units} \) at \( 90^\circ \)

**Graph Explanation:**
The provided graph is a Cartesian coordinate system with labeled axes, representing a vector addition problem.

**Vectors on the Graph:**
1. **Vector \( F_1 \) (Blue Arrow)**
   - Magnitude: 1.47 units
   - Direction: \( 0^\circ \) (positive x-axis)
   - Plotted from the origin (0,0) to the point (1.47, 0)

2. **Vector \( F_2 \) (Blue Arrow)**
   - Magnitude: 1.96 units
   - Direction: \( 90^\circ \) (positive y-axis)
   - Plotted from the origin (0,0) to the point (0, 1.96)

**Resultant Vector \( F_r \) (Black Arrow and Dotted Lines)**
- The resultant vector \( F_r \) starts from the origin and ends at the point where the two original vectors combine, forming the hypotenuse of the right triangle created by \( F_1 \) and \( F_2 \).
- Magnitude: Approximately 1.9 units
- Direction: \( 45^\circ \)

**Forming the Resultant Vector:**
The resultant vector \( F_r \) can be found by placing the tail of \( F_2 \) at the head of \( F_1 \). This forms a right triangle with:
- The horizontal component as \( F_1 \)
- The vertical component as \( F_2 \)

In accordance with the Pythagorean theorem, the magnitude of \( F_r \) is calculated as:
\[ F_r = \sqrt{F_1^2 + F_2^2} \]
\[ F_r = \sqrt{1.47^2 + 1.96^2} \approx 2.45 \text{ units} \]

**Conclusion:**
The graph visually demonstrates the vector addition process, with the components \( F_1 \) and \( F_2 \) and their resultant vector \( F_r \). This graphical method helps
Transcribed Image Text:### Vector Addition **Given Vectors:** - \( F_1 = 1.47 \, \text{units} \) at \( 0^\circ \) - \( F_2 = 1.96 \, \text{units} \) at \( 90^\circ \) **Graph Explanation:** The provided graph is a Cartesian coordinate system with labeled axes, representing a vector addition problem. **Vectors on the Graph:** 1. **Vector \( F_1 \) (Blue Arrow)** - Magnitude: 1.47 units - Direction: \( 0^\circ \) (positive x-axis) - Plotted from the origin (0,0) to the point (1.47, 0) 2. **Vector \( F_2 \) (Blue Arrow)** - Magnitude: 1.96 units - Direction: \( 90^\circ \) (positive y-axis) - Plotted from the origin (0,0) to the point (0, 1.96) **Resultant Vector \( F_r \) (Black Arrow and Dotted Lines)** - The resultant vector \( F_r \) starts from the origin and ends at the point where the two original vectors combine, forming the hypotenuse of the right triangle created by \( F_1 \) and \( F_2 \). - Magnitude: Approximately 1.9 units - Direction: \( 45^\circ \) **Forming the Resultant Vector:** The resultant vector \( F_r \) can be found by placing the tail of \( F_2 \) at the head of \( F_1 \). This forms a right triangle with: - The horizontal component as \( F_1 \) - The vertical component as \( F_2 \) In accordance with the Pythagorean theorem, the magnitude of \( F_r \) is calculated as: \[ F_r = \sqrt{F_1^2 + F_2^2} \] \[ F_r = \sqrt{1.47^2 + 1.96^2} \approx 2.45 \text{ units} \] **Conclusion:** The graph visually demonstrates the vector addition process, with the components \( F_1 \) and \( F_2 \) and their resultant vector \( F_r \). This graphical method helps
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