Eyplain the tremendous difference in pKa values for the following two apparently similar compounds. To Support your answer, include clear drawings/analysis of the relevant conjugate base(s) pka = 16 pka = 36

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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**Task:**

a) Explain the tremendous difference in pKa values for the following two apparently similar compounds. To support your answer, include clear drawings/analysis of the relevant conjugate base(s).

**Compounds:**

1. Cyclopentadiene

   - Structure: A five-membered ring with two double bonds and a single hydrogen at one carbon.
   - pKa = 16

2. Benzene

   - Structure: A six-membered ring with alternating double bonds (consistent with aromatic stability).
   - pKa = 36

**Explanation:**
The task requires a detailed comparison of the acidity in cyclopentadiene and benzene, focusing on the stability of their respective conjugate bases when they lose a proton. Consider factors such as aromaticity, electronic effects, and resonance stabilization.
Transcribed Image Text:**Task:** a) Explain the tremendous difference in pKa values for the following two apparently similar compounds. To support your answer, include clear drawings/analysis of the relevant conjugate base(s). **Compounds:** 1. Cyclopentadiene - Structure: A five-membered ring with two double bonds and a single hydrogen at one carbon. - pKa = 16 2. Benzene - Structure: A six-membered ring with alternating double bonds (consistent with aromatic stability). - pKa = 36 **Explanation:** The task requires a detailed comparison of the acidity in cyclopentadiene and benzene, focusing on the stability of their respective conjugate bases when they lose a proton. Consider factors such as aromaticity, electronic effects, and resonance stabilization.
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