EXTRA CREDIT. Two populations of snails live on opposite sides of a city. The frequency ofthe recessive allele (q) of a trait is 0.1 in the population on the north side of the city and 0.6 inthe population on the south side. Some individuals from the north side are moved to thesouth side. After migration, 8.5% of the individuals on the south side are migrants (originallyfrom the north side). Determine how this migration event affected q in the south sidepopulation. Round to the nearest thousandth. Express all values as a frequency in the format"0.###". What is the value of m?- What is q in the south side population after migration (aka, q')?

Step 1:To determine how the migration event affected the frequency of the recessive allele (q) in…

Answered: EXTRA CREDIT. Two populations of snails…

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter18: Genetics Of Behavior

Section: Chapter Questions

Problem 17QP: Genetics and Social Behavior Of the following findings, which does not support the idea that...

See similar textbooks

Similar questions

Show your work. Draw if needed
frequencies. Impacts of Natural Selection Read the following scenario. Use the Hardy-Weinberg principle and your knowledge of natural selection to explain the scientists' logic. Provide your answer in two standard paragraphs (four or five sentences each) using complete sentences. Refer to the given scenario in your answer. In an isolated population of 1,000 white-tailed deer, about 850 deer possess long legs. The dominant allele for leg length is long legs, and deer that are homozygous for this dominant allele or are heterozygous possess long legs. The population mates randomly and is stable. Living in a forest, they feed mostly on shrubs and the low-hanging leaves and branches of understory trees During the last 20 growing seasons, the shrub layer has slowly disappeared from the ecosystem. The population of deer adapted by foraging primarily on the leaves and branches of understory trees. Over browsing has occurred, and the understory trees have lost most of their leaves and tender…
CORRECT ANSWER ONLY. It is NOT option A.
Please do all. Choices are the same for all
asap please.
Need help.
Genetic HW Need help. Please step by step，show details.
An adaptation isa. any trait that arises from a mutation.b. a trait that increases the reproductive success of its bearer.c. any trait that changes during the lifetime of an organism.d. a trait that arises due to gene flow or genetic drift.
Population and Quantitative Genetics. Assume the mean value for Trait A in Generation 0 is 0.5. Mean value for those individuals that reproduce in Generation 0 is 0.75. Selection differential, S is 0.25. Predicted response to selection, R is 0.143. What is the predicted mean trait value in Generation 1?
the area titled Genotype Relative Fitness. Notice that the default is for all three genotypes to be set at 1.0. This indicates that all three genotypes have the same effect on survival and reproduction. Change the Genotype Relative Fitness of the rr genotype to 0.6. This indicates that the rr genotype (white phenotype) has a strong disadvantage over the other type genotypes in terms of survival and reproduction. Start the simulation and let it run for 200 generations. http://virtualbiologylab.org/ModelsHTML5/PopGenFishbowl/PopGenFishbowl.html When you started the simulation, your initial alleles frequencies were: R = 0.5 r = 0.5 What are your allele frequencies after 200 generations of strong selection?
Mutation O Silent mutation from one allele to another ■ Suppose one allele (A1) mutates to another (A2) at some rate, μ, each generation within a population, and A2 mutates to A1 at some other rate, v. Suppose also that A1 and A2 are selectively neutral - they confer equal fitness. what is the equilibrial frequency of each of the two alleles (p* and q*)? You can think of the mathematical result as p* being the mutation rate towards A1 divided by the sum of the mutation rates. OR, p* is the proportion of all mutation rates (µ+v) that is mutation in the A1 direction (v). See box 7.7. ● ● ● μ = mutation from A1 to A2 v = mutation from A2 to A1 p* = v/(μ+v) Example: A1 mutates to A2 in 0.0004 of all offspring per generation. In other words the probability of mutation from A1 to A2 is 0.0004. A2 mutates to A1 in 0.0001 of all offspring per generation. What is the expected equilibrial abundance A1 and A2? μ = mutation from A1 to A2 = 0.0004 v = mutation from A2 to A1 = 0.0001 p* = v/(μ+v) =…
Explain well. Asap

SEE MORE QUESTIONS

Recommended textbooks for you

Human Heredity: Principles and Issues (MindTap Co…

Biology

ISBN:

9781305251052

Author:

Michael Cummings

Publisher:

Cengage Learning

Biology Today and Tomorrow without Physiology (Mi…

Biology

ISBN:

9781305117396

Author:

Cecie Starr, Christine Evers, Lisa Starr

Publisher:

Cengage Learning

Human Heredity: Principles and Issues (MindTap Co…

Biology

ISBN:

9781305251052

Author:

Michael Cummings

Publisher:

Cengage Learning

Biology Today and Tomorrow without Physiology (Mi…

Biology

ISBN:

9781305117396

Author:

Cecie Starr, Christine Evers, Lisa Starr

Publisher:

Cengage Learning

SEE MORE TEXTBOOKS