When do scientists use the Hardy Weinberg Equation? After all, the conditions are never r met in the real world? Hardy Weinberg Alleles in a Population • Counting Alleles - assume 2 alleles B, b -frequency of dominant allele (B) = p -frequency of recessive allele (b) = q • frequencies must add to 1 (100%) , so: p+q=1 Bb BB p+q=1 B b bb Individuals in a population Counting Individuals -frequency of homozygous dominant: pxp=p² -frequency of homozygous recessive: qx q =q² -frequency of heterozygotes; (px q) + (q xp) = 2pq • frequencies of all individuals must add to 1 (100%), so: p² + 2pq+q² = 1 BB Bb bb When do you use each equation? You use P+Q=1 when: p² + 2pq+q² = 1 (ВВ) (Bb bb ● ● You use P2 + 2PQ+ Q² = when:

Human Anatomy & Physiology (11th Edition)
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Author:Elaine N. Marieb, Katja N. Hoehn
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Chapter1: The Human Body: An Orientation
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When do scientists use the Hardy Weinberg Equation? After all, the conditions are never really
met in the real world?
Hardy
Weinberg
Alleles in a Population
• Counting Alleles
- assume 2 alleles B, b
-frequency of dominant allele (B) = p
-frequency of recessive allele (b) = q
• frequencies must add to 1 (100 %), so:
p+q=1
Bb
BB
p+q=1
B b
bb
Individuals in a population
When do you use each equation?
You use P+Q=1 when:
Counting Individuals
-frequency of homozygous dominant: px p=p²
-frequency of homozygous recessive: qx q=q²
-frequency of heterozygotes; (px q) + (q xp) = 2pq
• frequencies of all individuals must add to 1 (100%), so:
p² + 2pq+q² = 1
BB
Bb
bb
p²+2pq+q2 = 1
(BB) Bb bb
●
●
You use P2 + 2PQ+Q² = when:
Transcribed Image Text:When do scientists use the Hardy Weinberg Equation? After all, the conditions are never really met in the real world? Hardy Weinberg Alleles in a Population • Counting Alleles - assume 2 alleles B, b -frequency of dominant allele (B) = p -frequency of recessive allele (b) = q • frequencies must add to 1 (100 %), so: p+q=1 Bb BB p+q=1 B b bb Individuals in a population When do you use each equation? You use P+Q=1 when: Counting Individuals -frequency of homozygous dominant: px p=p² -frequency of homozygous recessive: qx q=q² -frequency of heterozygotes; (px q) + (q xp) = 2pq • frequencies of all individuals must add to 1 (100%), so: p² + 2pq+q² = 1 BB Bb bb p²+2pq+q2 = 1 (BB) Bb bb ● ● You use P2 + 2PQ+Q² = when:
Expert Solution
Step 1

The Hardy-Weinberg principle is an important concept in population genetics. It states that, in the absence of other evolutionary influences, allele and genotype frequencies in a population will remain constant from generation to generation.

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