Express the confidence interval 64.4%±4.1%64.4%±4.1% in interval form.
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A: The sample size is, n = 45. The level of significance is, The degree of freedom is,
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A: Given Information: Confidence interval = (57.7% ± 9%)
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Q: construct a 99% confidence interval  n=34 x= 19.4 s= 4.3 Find the lower and upper bound (round to…
A: n=34 x¯=19.4 s=4.3 degrees of freedom(df)=n-1 df=34-1=33 α=1-0.99=0.01α2=0.005t0.005(33)=2.733…
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Q: If n=130 and p (p-hat) =0.53, find the margin of error at a 99% confidence level Give your answer to…
A: The sample size is .The sample proportion is .The confidence level is .
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A: Given, A researcher found that the margin of error ME = 0.9 and The sample mean u = 17.7 Find the…
Q: Sample A has 800 number of successes from a sample size of 805. Sample 8 has 792 number of successes…
A: Given that Sample A Sample B Sample size (n1) = 805 Sample size (n2) = 811 Number of…
Q: Express the confidence interval 22.5%<p<33.7% in the form of ˆp±ME. % ± %
A: The given confidence interval is (22.5%, 33.7%). Here, upper limit is 33.7 and lower limit is 22.5.
Q: You collect a random sample of 70 webpage load times in milliseconds (ms) from the server logs. The…
A: Given that, The degree of freedom is, df=n-1 =70-1 =69 Critical value: Using the t-table, the…
Q: A scientist claims that only 67% of geese in his area fly south for the winter. He tags 70 random…
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Q: Express trle 0.000
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Q: If n=100 and p' (p-prime) = 0.18, construct a 99% confidence interval. Give your answers to three…
A: Givenn=100p^=0.18confidence interval = 99%
Q: A sample of 36 men has a mean weight of 175 pounds with a sample standard deviation of 13 pounds.…
A: It is given that sample mean is 175 and standard deviation is 13.
Q: Express the confidence interval 48.9%±8.8%48.9%±8.8% in interval form.
A:
Q: Express the confidence interval (45.3%,59.3%)(45.3%,59.3%) in the form of ˆp±MEp^±ME. % ± %
A: The margin of error is, Thus, the margin of error is 0.07.
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Q: Express the confidence interval (19.1%,34.5%)(19.1%,34.5%) in the form of ˆp±Ep^±E. . % ± .…
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A:
Q: Express the confidence interval 46.7%±5.1%46.7%±5.1% in interval form.
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Q: ou collect a random sample of 66 webpage load times in milliseconds (ms) from the server logs. The…
A: Given data, n=66 x=397 s=33.7 Alpha=0.01 df=n-1=65 t-critical value is tc=2.653
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Q: Express the confidence interval 44.1%±7.6%44.1%±7.6% in interval form.
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Q: A random sample of 68 lunch customers was taken at a restaurant. The average amount of time the…
A: Given Data: x¯=42s=11n=68 Degree of freedom=n-1=68-1=67
Q: Express the confidence interval 74.1%±4.2%74.1%±4.2% in interval form
A: Express the confidence interval 74.1%±4.2%74.1%±4.2% in interval form
Q: Express the confidence interval 27.3%±8.3%27.3%±8.3% in interval form.
A: Given that, Confidence Interval = 27.3% ± 8.3%
Q: If n=130 and ôp (p-hat) =0.93, find the margin of error at a 99% confidence level Give your answer…
A: Here, the margin of error for proportion p^ is to be calculated. The formula is given by, z*p^1-p^n,…
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Q: Express the confidence interval 71.5%±6.9%71.5%±6.9% in interval form.
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Q: Express the confidence interval 0.814 +0.058 in open interval form (i.e., (0.155,0.855)).
A: Confidence interval : C.I = [0.814 ± 0.058] Confidence interval is the range of values , which gives…
Q: Express the confidence interval 0.784 ± 0.049 in open interval form (i.e., (0.155,0.855)).
A: Given Confidence interval is 0.784±0.049.
Q: If n = 140 and p (p-hat) = 0.8, construct a 95% confidence interval. %3D Give your answers to three…
A: We want to find the 95% CI for population proportion
Express the confidence interval 64.4%±4.1%64.4%±4.1% in interval form.
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- Express the confidence interval 0.856±0.084 in open interval form (i.e., (0.155,0.855)). ___________________________Express the confidence interval (0.017,0.095) in the form of p-EExpress the confidence interval (35,59) in the form of sample mean ± ME.Construct the 9292% confidence interval estimate of the population proportion ?p if the sample size is ?=200n=200 and the number of successes in the sample is ?=118.x=118. <?<<p<Express the confidence interval (0.056,0.124) in the form of P-EA scientist claims that only 67% of geese in his area fly south for the winter. He tags 70 random geese in the summer and finds that 20 of them do not fly south in the winter. If α= 0.05, is the scientist's belief warranted? Test by using confidence interval. Round confidence interval to nearest thousandth. Show step1-step3 included conclusion.Recommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons Inc
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