Answered: Express the confidence interval…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. From a random sample of 75 dates, the mean record high daily temperature in a certain city has a mean of 82.23°F. Assume the population standard deviation is 14.04°F. The 90% confidence interval is ( ). (Round to two decimal places as needed.)
A researcher was interested in comparing weekly salaries between men and women. Independent samples were drawn to find the average salary for each group. A 90% confidence interval for the difference between female and male employees was determined to be (-$110, $10) in a given week. Interpret the confidence interval Zero is contained in the interval so the probability that male employees earn the same as females is 0.9. 90% of the time, women earn less than men. ore per ek Based on these data, we would assume that female employees average between $110 and $10 than male employees O We are 90% confident that men earn between $110 less or $10 more than women in a given week.
Express the confidence interval (0.056,0.124) in the form of P-E
What price do farmers get for their watermelon crops? In the third week of July, a random sample of 45 farming regions gave a sample mean of = $6.88 per 100 pounds of watermelon. Assume that σ is known to be $1.98 per 100 pounds. (a) Find a 90% confidence interval for the population mean price (per 100 pounds) that farmers in this region get for their watermelon crop (in dollars). What is the margin of error (in dollars)? (For each answer, enter a number. Round your answers to two decimal places.)lower limit $ upper limit $ margin of error $ (b) Find the sample size necessary for a 90% confidence level with maximal error of estimate E = 0.45 for the mean price per 100 pounds of watermelon. (Enter a number. Round up to the nearest whole number.) farming regions (c) A farm brings 15 tons of watermelon to market. Find a 90% confidence interval for the population mean cash value of this crop (in dollars). What is the margin of error (in dollars)? Hint: 1 ton is 2000…
Express the confidence interval 33.4%<p<43.6%33.4%<p<43.6% in the form of ˆp±Ep^±E.
Construct a confidence interval for P₁-P₂ at the given level of confidence. X₁ = 369, n₁ = 508, X₂ = 426, n₂ = 599, 95% confidence % The researchers are confident the difference between the two population proportions, P₁-P₂, is between and (Use ascending order. Type an integer or decimal rounded to three decimal places as needed.)
Express the confidence interval 85.9%<p<91.9%85.9%<p<91.9% in the form of ˆp±Ep^±E.% ± %
A scientist claims that only 67% of geese in his area fly south for the winter. He tags 70 random geese in the summer and finds that 20 of them do not fly south in the winter. If α= 0.05, is the scientist's belief warranted? Test by using confidence interval. Round confidence interval to nearest thousandth. Show step1-step3 included conclusion.
Suppose that a garage finds that 30 customers of 138 customers samples get their oil changes on time. Find a 98% confidence interval of the true proportion. What is the upper bound of the confidence interval? (round to 4 decimal places)
A random sample of 1700 car owners in a particular city found 816 car owners who received a speeding ticket this year. Using the Wilson "plus four" technique, find a 95% confidence interval for the true percent of car owners in this city who received a speeding ticket this year. Express your results to the nearest hundredth of a percent.
In a random survey of 406 people, 295 indicated that they prefered to go a forest to camp. Find a 83% confidence interval for the true proportion of all people who prefer to go to a forest to camp. (Round answers to three decimal places.) Error =

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Express the confidence interval 48.9%±8.8%48.9%±8.8% in interval form.