Fron a random sample of 500 Google play apps with more than 1 million installs, 498 are free. Find and interpret a 95% confidence interval for the population proportion of free apps with more than 1 million installs. Write your interval up to 4 decimal places.

Q: A survey of 700 non-fatal accidents showed that 167 involved uninsured drivers. Construct a 99%…

A: Given data,n=700x=167Point estimate isp=xn=167700=0.2386Construct a 99% confidence interval?

Q: According to a national statistics bureau, 3.7% of males living in the Southwest were retired…

A: Given Information: 3.7% of males living in the Southwest were retired exterminators. i.e.,p0 =…

Q: For EACH of the 2 majors, consider the 'School Type' column. Construct a 90% confidence interval for…

A: Confidence Interval: The form of the confidence interval is, CI = Point estimate ± Margin of error…

Q: he effects of mentoring on intelligence scores. He wanted to know as a baseline what the averag

A: mean(μ)=100standard deviation(σ)=16  n=50    let X~N(100,16)

Q: The mean hours of worked for United Airlines pilots is 46 hours/month based upon a sample of 25…

A: Given: Sample size, n=25 Sample mean, X=46 hours Sample standard deviation, s=3 hours The level of…

Q: A survey of 425 randomly selected students at one university found that 300 students think they…

A:

Q: A survey of  1000  U.S. adults found that  34%  of people said that they would get no work done on…

A: Sample size n=1000 Sample proportion p^=0.34

Q: A recent survey showed that among 850 randomly selected subjects who completed 4 years of college,…

A: I'm providing the solution below please do refer it and let me know if you have any queries…

Q: Suppose that a 92% Confidence Interval for estimating the average heights, in inches, of all college…

A: confidence interval = x ± margin of errorlower limit = x - margin of errorupper limit = x + margin…

Q: A survey of 800 adults found that 32% of people said that they would get no work done on cyber…

A: Given  n=800, pcap=0.32, Zcritical=1.96 at alpha=0.05 We want to find 95% CI for population…

Q: A research found that 70% of 1500 randomly selected U.S. adults believe in global warming. Find the…

A: Solution: From the given information, p-hat=0.70 and n=1500.

Q: In a study of 120 randomly selected families, 50 said they streamed their television content. Find…

A:

Q: A software company is interested in improving customer satisfaction rate from the 65% currently…

A: Given,population proportion(P)=0.65sample size(n)=207no.of customers who were satisfied(x)=145

Q: Show the steps needed to justify and use a normal model to describe the percentage of women with…

A: Medical Researcher believe that 11% of women have a certain generic marker.  A survey team will…

Q: Out of 400 people sampled, 68 had kids. Based on this, construct a 99% confidence interval for the…

A: Solution: Let X be the number of people had kids and n be the number of people sampled. From the…

Q: A study at Harvard found that 44% of their students binge drink. You are at Princeton doing a…

A:

Q: Most adults would erase all information online if they could 113 random selected adults showed that…

A: The random variable erase all of their personal information online is normally distributed. The…

Q: A report statesb that 44% of home owners had a vegetable garden. how large a sample is needed to…

A: Answer: Using the given data, A report stated that 44% of home owners had a vegetable garden, P =…

Q: You measure 49 backpacks' weights, and find they have a mean weight of 69 ounces. Assume the…

A: Solution:Given information:

Q: In a sample of 550 adults, 512 had children. Construct a 99% confidence interval for the true…

A: Given X=512 n=550

Q: A random sample of 100 employees at a company shows that 62 are female.  Form a 95% confidence…

A:

Q: In a survey, 24 people were asked how much they spent on their child's birthday party. The results…

A: Introduction: The 100 (1 – α) % confidence interval for the population mean, μ, when the population…

Q: A pollster asked a random sample of 269 students about their savings. The average amount of money…

A: The sample size is 269, sample mean is $258, and sample standard deviation is $145. The degrees of…

Q: more than 50% Australians would download COVIDSafe app? Check the condition and test at 5% level.

A:

Q: You want to get a 95% confidence interval for the difference between the percentage of females with…

A:

Q: You measure 44 dogs' weights, and find they have a mean weight of 80 ounces. Assume the population…

A: You measure 44 dogs' weights, and find they have a mean weight of 80 ounces. Assume the population…

Q: A sample of 175 U.S. adults is composed of 100 women and 75 men. What is the estimate of the true…

A: Given problem Given that

Q: Construct the 99.8% confidence interval for the difference P1 - P2 when x, = 23, n, = 53, x2 = 15,…

A:

Q: A recent study by the McGraw-Hill company showed that 61% (1621) of college students use their…

A: Given, Proportion of college students use their smartphones for study = 0.61Total number of students…

Q: A poll showed that 385 out of 700 adults said they would be interested in traveling to outer space…

A: This question requires accurate results, Hence I will use excel to solve this question.…

Q: Compute the probability of successfully completing the task for an engineer having 24 months of…

A: Given the data of monthly experience of the task is a success or not for 2 engineers as shown below…

Q: Nearly one-half of Americans ages 25 to 29 are unmarried. How large a sample is necessary to…

A: The provided information is The margin of error is E=0.02 α=0.05 The critical value is zc=1.96…

Q: You measure 35 backpacks' weights, and find they have a mean weight of 64 ounces. Assume the…

A: n = 35x¯ = 64σ = 499% ci for μ = ?

Q: In a sample of 460 adults, 281 had children. Construct a 90% confidence interval for the true…

A:

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.