Express the confidence interval 30.7 %
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A: Given: Confidence interval = ( 12.5 , 22.3 ) To find: Sample mean and margin of error
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A: Given observation 27 18 26 18 16 20 10 20 19 19 28 14 27
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A: Given that there are 500 people sampled and 421 responded that they own cell phones. The residents…
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Q: A random sample of 1700 car owners in a particular city found 799 car owners who received a speeding…
A: Given,n=1700x=799p^=xnp^=7991700=0.471-p^=1-0.47=0.53α=1-0.95=0.05α2=0.025Z0.025=1.96 (from…
Q: Suppose it is hypothesized that 65% of students support the use of low-cost textbooks. A survey of…
A: Assume that p is the true proportion of students who supports the use of low-cost.
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A: A computer company has imported a shipment of devices, and the exporting company has pledged that…
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Q: A U.S. Travel Data Center survey conducted for Better Homes and Gardens of 1500 adults found that…
A: Given: sample size, n=1500 sample proportion, p = 0.39
Q: Out of 300 people sampled, 27 had kids. Based on this, construct a 90% confidence interval for the…
A: Sample size n =300 Favorable cases x =27 Sample proportion p^=x/n =27/300 =0.09
Q: college performs a survey of 424 randomly chosen graduates to estimate the proportion of alumni who…
A: We have given that Sample size n =424 Favorable cases x =361 Sample proportion p^=x/n =361/424…
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A: Given, The sample proportion is,
Q: A random sample of 5008 adults in a country includes 760 who do not use the Internet. Construct a…
A: n=5008x=760
Q: Express the confidence interval ( 26.2%, 35.2%) in the form of p-hat plus or minus M.E.
A: Given Conference interval = (26.2℅ , 35.2℅) =(0.262 , 0.352)
Q: Express the confidence interval 75.7% < p < 85.1% in the form of p± E. %+ Submit Question
A: We have given Information, Confidence interval for population proportion p is: 75.7%<p<85.1%…
Q: Express the confidence interval 57.2 % < p < 71.4 % in the form of p + E. % +
A: From the provided information Confidence interval 57.2% < p < 71.4%
Q: A U.S. Travel Data Center survey conducted for Better Homes and Gardens of 1500 adults found that…
A: Solution: Given information: n= 1500 Sample size p^= 0.39 Sample proportion
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A: From given data n=96 mean=9% standard deviation=9% confidence interval=99%
Q: Express the confidence interval (16.4 % , 31.8 % ) in the form of p + E. Submit Question
A: We have to convert ci in given form.
Q: A study of 420,029 cell phone users found that 132 of them developed cancer of the brain or nervous…
A: From the provided information Confidence level = 95% Sample size (n) = 420029 132 of them developed…
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A: Given 99% CI for population proportion of all students at this college is (0.78,0.98)
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A: It is given that sample size n =100 and x =88.
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A: Here, we have to compute 90% confidence interval for the true proportion of adult residents of this…
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- A random sample of 336 medical doctors showed that 160 had a solo practice. (a) Let p represent the proportion of all medical doctors who have a solo practice. Find a point estimate for p. (Use 3 decimal places.) (b) Find a 95% confidence interval for p. (Use 3 decimal places.) lower limit upper limit What is the margin of error based on a 95% confidence interval? (Use 3 decimal places.)Find the confidence intervalInterpret a confidence interval: A survey organization drew a simple random sample of 625 households from a city of 100,000 households. The sample mean of people in the 625 households was 2.30, and a 95% confidence interval for the mean number of people in the 100,000 households was 2.16< sum of mean< 2.44. True or false explain. The probability is 0.95 that the mean number of people in 100,000 households is between 2.16 and 2.44.
- Out of 500 people sampled, 290 voted in the last election. Based on this, construct a 99% confidence interval for the true population proportion of people who voted in the last election. Give your answers as decimals, to three placesExpress the confidence interval (59%,67.6%) in parts p and e use decimals not percentage p= e=A flu shot is administered during flu season. We look at the effect of the shot on individuals who received the shot versus those who did not. In a sample of 100 patients that received the flu shot, the average recovery time after being infected with the flu was 4 days with a standard deviation of 1 day. What is a 95% confidence interval for the population average recovery time? O (3.99.4.01) (3.80, 4.20)It is of interest to know if the average time it takes police to reach the scene of an accident differs from that of an ambulance to reach the same accident. Estimate the difference in the times between the police and the ambulance (mean time for police - mean time for ambulance) using a 99% confidence interval. Based on the confidence interval constructed, do the data support the claim that it takes the same amount of time for the police and the ambulance to reach the scene of an accident? Summary data are as follows: sample size sample mean sample variance Police 60 4.2 minutes 0.08 Ambulance 55 4.5 minutes 0.10 Group of answer choices A. 99% C.I. is (-0.445, -0.155). The sample supports that the times differ. B. 99% C.I. is (-1.070, 0.471). The sample does not supports that the times differ. C. 99% C.I. is (-0.445, -0.155). The sample does not support that the times differ. D. 99% C.I. is (-1.070, 0.471). The sample supports that the times differ.A confidence interval was used to estimate the proportion of math majors that are female . A random sample of 72 math majors generated the confidence interval (0.438, 0.642) . Using the information above , what size sample would be necessary to estimate the true proportion to within 5% using 98% reliability95% ciA large multinational corporation recently implemented an ERP system. A survey was done to determine the level of satisfaction with the new system. Out of the 350 managers surveyed, 280 indicated that they were satisfied. - What is the lower limit of the 95% confidence interval on the proportion of satisfied managers? (three decimal places) -What is the upper limit of the 95% confidence interval on the proportion of satisfied managers? (three decimal places)A random sample of 1700 car owners in a particular city found 816 car owners who received a speeding ticket this year. Using the Wilson "plus four" technique, find a 95% confidence interval for the true percent of car owners in this city who received a speeding ticket this year. Express your results to the nearest hundredth of a percent.A study of 420,057 cell phone users found that 134 of them developed cancer of the brain or nervous system. Prior to this study of cell phone use, the rate of such cancer was found to be 0.0318% for those not using cell phones. Complete parts (a) and (b) a. Use the sample data to construct a 90% confidence interval estimate of the percentage of cell phone users who develop cancer of the brain or nervous system. %Recommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons Inc
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