S P(A/B) = A Let event A = Student belongs to at least one club on campus and event B = Student participates in team sports on campus P(B|A) = ANB At AnyTown Polytechnic College, 42% of students belong to a campus club, 38% of students participate in team sports, and 5% belong to at least one campus club and participate in team sports. Compute the probabilities requested below. Round all probabilities to four decimal places, as needed. P(An B)= P(ANB) = B

S P(A/B) = A Let event A = Student belongs to at least one club on campus and event B = Student participates in team sports on campus P(B|A) = ANB At AnyTown Polytechnic College, 42% of students belong to a campus club, 38% of students participate in team sports, and 5% belong to at least one campus club and participate in team sports. Compute the probabilities requested below. Round all probabilities to four decimal places, as needed. P(An B)= P(ANB) = B

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Question

S
P(A/B):
A
Let event A = Student belongs to at least one club on
campus
and event B = Student participates in team sports on
campus
P(B|A) =
ANB
At AnyTown Polytechnic College, 42% of students
belong to a campus club, 38% of students participate in
team sports, and 5% belong to at least one campus club
and participate in team sports. Compute the probabilities
requested below. Round all probabilities to four decimal
places, as needed.
P(ANB) =
P(AnB):
B

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Follow-up Questions

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Follow-up Question

Use the below information to answer the questions attached ;

Step 1

event A : student belongs to atleast one club on campusevent

B : student participates in team sports on campus

P(A) = 0.42P(B) = 0.38P(A∩B) = 0.05

Step 2

(a) P(A|B) = P(A∩B)P(B) = 0.050.38 = 0.1316

(b) P(B|A) = P(A∩B)P(A) = 0.050.42 = 0.1190

(d) P(A∩B¯) = 1 - P(A∩B) = 1 - 0.05 = 0.95

Explain the probabilities, indicated below, you found in
the previous problem.
Assume you randomly select a student who
[Select ]
represents the probability that this student also
[ Select ]
on campus. P(A/B)
Assume you randomly select a student who
[Select ]
on campus.
campus.
represents the probability that this student also
[Select]
on campus. P(B|A)
campus.
P(ANB) represents the probability that a randomly
selected student [Select]
on campus.
on
P(ANB) represents the probability that a randomly
selected student [Select]
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