If two events, A and B, are such that P(A) = 1/6, P(AUB) = 11/30, and P(An B) = 1/42, find t 1. P₁ = P(B | A); 2. P₂ = P(B);
If two events, A and B, are such that P(A) = 1/6, P(AUB) = 11/30, and P(An B) = 1/42, find t 1. P₁ = P(B | A); 2. P₂ = P(B);
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
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Transcribed Image Text:If two events, A and B, are such that P(A) = 1/6, P(AUB) = 11/30, and P(AB) = 1/42, find the following probabilities:
1. P₁ = P(B | A);
2. p₂ = P(B);
3. P3 = P(A | B);
4. P4 = P(A | Bº).
(P1, P2, P3, P4) =(__
Expert Solution
Step 1
Given that
P(A)=1/6 , P(A U B)=11/30 and
P(A ∩ B)=1/42
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Follow-up Question
Find P4
Transcribed Image Text:If two events, A and B, are such that P(A) = 1/6, P(AUB) = 11/30, and P(AB) = 1/42, find the following probabilities:
1. P₁ = P(B | A);
2. p₂ = P(B);
3. P3 = P(A | B);
4. P4 = P(A | Bº).
(P1, P2, P3, P4) =(__
Solution
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