Forty-six percent of adults did not visit their physicians' offices last year. Let X be the numberof adults in a random sample of twelve adults who did not visit their physician's office lastyear. Let P₁, P2, P3, and P4 be the probabilities, respectively, that the number of adults whodid not visit their physician's office last year will be:• exactly one;• two or more;• fewer than three;• between seven and nine, inclusive.Then the values of P₁, P2, P3, and P4 are, respectively, (Choose one from the followingwhich is closest to the correct answer)O d. 0.0063, 0.9931, 0.0363, 0.1163.a. 0.0069, 0.9637, 0.0363, 0.2748.O b. 0.0063, 0.9931, 0.0363, 0.2748.O e. 0.0063, 0.9637, 0.0363, 0.2748.c. 0.0063, 0.9931, 0.1199, 0.2748.

Forty-six percent of adults did not visit their physicians' offices last year. Let X be the number…

Answered: Forty-six percent of adults did not…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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В. Forty five percent of the streets in an area have private guards for security. Three streets are selected at random: i. What is the probability all three of the selected streets have private guards? What is the probability none of the three selected streets has private guards? What is the probability at least one of the selected streets has private guards? iv. ii. iii. What is the probability at most two of the selected streets have private guards?
At a company, the employees were surveyed and classified according to their level of education and whether they smoked or not. The data are shown in the table. High school graduate College graduate Smoke 09 19 Do not Smoke 17 25 If an employee is selected at random, find the following probabilities. (Round your answers to three decimal places) a. Employee smokes and is a college graduate. b. Employee smokes or is a college graduate. c. Employee smokes, given that he or she graduated from college. d. Employee is a college graduate, given that he or she smokes.
The percentage of mechanical-, civil-, aeronautical-, industrial-, and chemical-engineer- ing students in the course, Engineering Mathematics, is, respectively, 25, 20, 15, 22, and 18. The probability of a mechanical-, civil-, aeronautical-, industrial-, and chemical-en- gineering students getting the grade A is 0.7, 0.6, 0.8, 0.5, and 0.65, respectively. If a student chosen at random at the end of the semester earned an A in the course, find the probability of the student belonging to mechanical engineering.
Let A and B be mutually exclusive events, such that P(A) = = 0.9304 and P(B) = 0.0423 . Find the following probabilities: P(A and B)= % (Round the answer to 2 decimals) P(A or B)= % (Round the answer to 2 decimals)
It is known that 20 percent of all persons given a certain medication get drowsy within two minutes. Find the probabilities that among fourteen persons given medication a) b) c) at most two will get very drowsy within two minutes; at least five will get very drowsy within two minutes; two, three, or four will get very drowsy within two minutes. 15 pts
D An oil company purchased an option on land in Alaska. Preliminary geologic studies assigned the following prior probabilities. P(high-quality oil) = 0.40 P(medium-quality oil) = 0.25 P(no oil) = 0.35 a. What is the probability of finding oil (to 2 decimals)? b. After 200 feet of drilling on the first well, a soil test is taken. The probabilities of finding the particular type of soil identified by the test are given below. P(soil|high-quality oil) = 0.25 P(soil|medium-quality oil) = 0.90 P(soil|no oil) = 0.25 %3D Given the soil found in the test, use Bayes' theorem to compute the following revised probabilities (to 4 decimals). P(high-quality oil|soil) P(medium-quality oil soil) P(no oil soil) What is the new probability of finding oil (to 4 decimals)? According to the revised probabilities, what is the quality of oil that is most likely to be found? - Select your answer -
Two motels are up for sale. The following two tables give the number of rooms rented per day together with the associated probabilities (P). Motel 1 Number of rooms 5 6 7 8 9 10 P 0.06 0.11 0.33 0.23 0.2 0.07 Motel 2 Number of rooms 3 4 5 6 7 P 0.05 0.06 0.11 0.23 0.55 The average profit per room rented at the first motel is $28 and the average profit per room rented at the second motel is $37. Which motel will yield the higher daily profit? Motel 1 or Motel 2
Brian, a landscape architect, submitted a bid on each of three home landscaping projects. He estimates that the probabilities of winning the bid on Project A, Project B, and Project C are 0.7, 0.5, and 0.2, respectively. Assume that the probability of winning a bid on one of the three projects is independent of winning or losing the bids on the other two projects. Find the probability that Brian will experience the following. (a) Win all three of the bids (b) Win exactly two of the bids (c) Win exactly one bid
Find P(A or B or C) for the given probabilities. P(A) = 0.34, P(B) = 0.25, P(C) = 0.16 P(A and B) = 0.11, P(A and C) = 0.03, P(B and C) = 0.07 P(A and B and C) = 0.01 P(A or B or C) =
According to Mendel’s theory, if tall and colorful plants are crossed with short and colorless plants, the corresponding probabilities are 9/16, 3/16, 3/16, and 1/16 for tall and colorful, tall and colorless, short and colorful, and short and colorless, respectively. If 8 plants are selected, find the probability that 1 will be tall and colorful, 3 will be tall and colorless, 3 will be short and colorful, and 1 will be short and colorless.(4 decimal digits)
A random sample of 1000 adults has the elements of the sample classified by sex (= Male or Female) and educations ( = College, high School or Elementary). The results are summarized in the contingency table below. College High School Elementary Male 130 270 140 Female 170 180 110 Find the probability that a randomly selected person who is selected from the survey members is male, given that the individual finished college.
At the beginning of each day, a patient in the hospital is classifed into one of the three conditions: good, fair or critical. At the beginning of the next day, the patient will either still be in the hospital and be in good, fair or critical condition or will be discharged in one of three conditions: improved, unimproved, or dead. The transistion probabilities for this situation are Good Fair Critical Good 0.65 0.20 0.05 Fair 0.50 0.30 0.12 Critical 0.51 0.25 0.20 Improved Unimproved Dead Good 0.06 0.03 0.01 Fair 0.03 0.02 0.03 Critical 0.01 0.01 0.02 For example a patient who begins the day in fair condition has a 12% chance of being in critical condition the next day and a 3%…

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