Explain the basis for the following statement. For efficient conver- sion of galactose to glucose-1-phosphate, UDP-glucose need be present in catalytic amounts only.
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UDP : Uridine diphosphate glucose is a nucleotide sugar. It is involved in glycosyltransferase reactions in metabolism.
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- Consider the following list of phosphorylated compounds with their free energy changes of phosphate hydrolysis: Glucose-1-phosphate (-5.0 kcal/mol), PEP (-14.8 kcal/mole), 1,3-bisphosphoglycerate (-11.8 kcal/mole) and Glucose-6-Phosphate (-3.3 kcal/mol). Given that the free energy change of ATP hydrolysis is -7.3 kcal/mole, which of these molecules be directly synthesized by the transfer of a phospho- group from ATP? 1,3-bisphosphoglycerate Glucose-6-phosphate All of those phosphorylated compounds. PEP Glucose-1-phosphateLithium ion inhibits the synthesis of inositol trisphosphate by inhibiting a reaction in the breakdown of inositol trisphosphate.Explain this apparent paradox.Lithium ion inhibits the synthesis of inositol trisphosphate by inhibiting a reaction in the breakdown of inositol trisphosphate. Explain this apparent paradox.
- During glycogen synthesis, glucose-1P is converted into a molecule called UDPG. This reaction also cleaves uridine triphosphate (UTP) forming uridine monophosphate and pyrophosphate (PPi). Provide four reasons why UTP can be used to power this reaction (no diagrams necessary).The effect of ATP on the allosteric enzyme PFK-1 is shown below. For a given concentration of fructose 6-phosphate, the PFK-1 activity increases with increasing concentrations of ATP, but a point is reached beyond which increasing the concentration of ATP inhibits the enzyme. (a) Explain how ATP can be both a substrate and an inhibitor of PFK-1. How is the enzyme regulated by ATP? (b) In what ways is glycolysis regulated by ATP levels? (c) The inhibition of PFK-1 by ATP is diminished when the ADP concentration is high, as shown in the illustration. How can this observation be explained? *A graph is included for this question*Intramitochondrial ATP concentrations are about 5 mM, and phos- phate concentration is about 10 mM. If ADP is five times more abundant than AMP, calculate the molar concentrations of ADP and AMP at an energy charge of 0.85. Calculate AG for ATP hydrolysis at 37 °C under these conditions. The energy charge is the concentra- tion of ATP plus half the concentration of ADP divided by the total adenine nucleotide concentration: [ATP] + 1/2[ADP] [ATP] + [ADP] + [AMP]
- Consider the mechanism of enolase, as indicated below. Which of the following correctly describes the roles of the Mg2+ as illustrated in the figure? (This is a multi- select question). Mg2+ Mg2 Enolase PO3- OH -C-C-H H OH HO H-N-H Lys 345 Glu211 2-Phosphoglycerate bound to enzyme Mg2+ Mg2 PO3- OH C-C-H OH HO H H-N*-H Lys 345 O Glu211 Enolic intermediate HOH PO3- H Phosphoenolpyruvate The metal ion (Mg2+) is helping to stabilize the extra negative charge that developed on the carboxyl group in the enolic intermediate. The metal ion (Mg2+) is serving as a general base, removing a proton in order to improve the quality of the nucleophile. The metal ion (Mg2+) is assisting in the oxidation of the carboxyl carbon through metal ion catalysis. The metal ion (Mg2+) is helping to orient the substrate properly in the active site. The metal ion (Mg2+) is accepting a proton in order to improve the quality of the leaving group.The final step in the pathway for the synthesis of glucose from lactate (gluconeogenesis) is: Glucose-6-phosphate + H20 5 Glucose + Pi When glucose-6-phosphate is incubated with the proper enzyme and the reaction runs until equilibrium has been reached, the final concentrations are found to be: glucose-6-phosphate (0.035 mM), glucose (100 mM), and Pi (100 mM). Calculate AG" at 25°C and pH 7. 10:21 PM 4/21/2021 F5 F6 F7 F8 F10 F9 7 8. Backspace ー のThe reaction catalyzed by phosphorylase is readily reversible in vitro. At pH 6.8, the equilibrium ratio of orthophosphate to glucose 1-phosphate is 3.6. The value of ΔG°’ for this reaction is small because a glycosidic bond is replaced by a phosphoryl ester bond that has a nearly equal transfer potential. However, phosphorolysis proceeds far in the direction of glycogen breakdown in vivo. Suggest one means by which the reaction can be made irreversible in vivo.
- Galactose 1-phosphate: UDP-glucose uridyltransferase (GALT) is an enzyme important for the catabolism of galactose. Patients with GALT deficiency present within days of birth with feeding difficulty, fatigue, jaundice and liver problems, and failure to thrive. In addition, a buildup of galactose and its metabolites are present in the bloodstream. GALT catalyzes the following reaction in galactose catabolism. NOTE that GALT is reversible!! Classify this enzyme and explain why you classified it in this way.Hexokinase catalyzes the first step of glycolysis, in which glucose is phosphorylated to form glucose‑6‑phosphate. Give two reasons why a Mg2+ cation is required to facilitate this reaction.Consider the complete oxidation of one mole of simple TAG containing behenic acid residues (22:0). I. For one mole of the fatty acid residue, determine the following: c. What is the number of ATP yield obtained from FADH2 coming from the complete β-oxidation of the fatty acid residue