Explain – based solely on thermodynamic considerations – why the energy density of a photon cavity is proportional to T^4, independent of the size, shape and material of the cavity.
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A: v=hmλ=6.63×10-34 J·s 1.675×10-27 kg0.200 nm10-9 m1 nm=1.98×103 m/s
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A: Given Data: Kinetic energy (K) = 13.6 eV = 13.6×1.6×10-19 J = 21.76×10-19 J.Radius (r) = 0.0529 nm =…
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Q: Ex. 57: The threshold wavelength for photonmission from silver is 3800 Å. Calculate the maximum…
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Q: Explain-based solely on thermodynamic considerations why the energy density of a photon cavity is…
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Q: Part a) Find the total energy (in J) of 2.158 x 10^19 photons of red light (λ=675 nm)? Part b)…
A: Given: Number of photons, N = 2.158×1019 Wavelength of the photon, λ = 675 nm = 6.75×10-7 m…
Q: Outline the steps leading to the formula for the number of photons with angular fre- quencies…
A: We will first calculate the number of modes of oscillations of EM waves possible in a cavity.…
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