Calculate the frequency and momentum of a photon of wavelength 620 nm.

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**Physics Problem: Calculating Photon Characteristics**

**Problem Statement:**
Calculate the frequency and momentum of a photon of wavelength 620 nm.

**Detailed Explanation:**

This problem involves the calculation of two key characteristics of a photon: its frequency and momentum.

1. **Frequency Calculation:**
   - The frequency (\( f \)) of a photon can be calculated using the equation:
     \[
     f = \frac{c}{\lambda}
     \]
     where \( c \) is the speed of light in a vacuum (\( c \approx 3 \times 10^8 \) meters/second) and \( \lambda \) is the wavelength of the photon.
   - For a photon of wavelength 620 nm (nanometers), convert this to meters:
     \[
     \lambda = 620 \times 10^{-9} \text{ meters}
     \]
   - Substituting the values into the formula:
     \[
     f = \frac{3 \times 10^8}{620 \times 10^{-9}}
     \]
   - Calculate the resulting frequency.

2. **Momentum Calculation:**
   - The momentum (\( p \)) of a photon can be calculated using the equation:
     \[
     p = \frac{h}{\lambda}
     \]
     where \( h \) is Planck's constant (\( h \approx 6.626 \times 10^{-34} \) joule-seconds) and \( \lambda \) is the wavelength of the photon.
   - Again, for a photon of wavelength 620 nm, substituting the values into the formula:
     \[
     p = \frac{6.626 \times 10^{-34}}{620 \times 10^{-9}}
     \]
   - Calculate the resulting momentum.

This problem demonstrates the application of fundamental physics equations to determine the properties of photons, fundamental particles of light. These calculations are pivotal in quantum mechanics, optics, and various applications in physics and engineering.
Transcribed Image Text:**Physics Problem: Calculating Photon Characteristics** **Problem Statement:** Calculate the frequency and momentum of a photon of wavelength 620 nm. **Detailed Explanation:** This problem involves the calculation of two key characteristics of a photon: its frequency and momentum. 1. **Frequency Calculation:** - The frequency (\( f \)) of a photon can be calculated using the equation: \[ f = \frac{c}{\lambda} \] where \( c \) is the speed of light in a vacuum (\( c \approx 3 \times 10^8 \) meters/second) and \( \lambda \) is the wavelength of the photon. - For a photon of wavelength 620 nm (nanometers), convert this to meters: \[ \lambda = 620 \times 10^{-9} \text{ meters} \] - Substituting the values into the formula: \[ f = \frac{3 \times 10^8}{620 \times 10^{-9}} \] - Calculate the resulting frequency. 2. **Momentum Calculation:** - The momentum (\( p \)) of a photon can be calculated using the equation: \[ p = \frac{h}{\lambda} \] where \( h \) is Planck's constant (\( h \approx 6.626 \times 10^{-34} \) joule-seconds) and \( \lambda \) is the wavelength of the photon. - Again, for a photon of wavelength 620 nm, substituting the values into the formula: \[ p = \frac{6.626 \times 10^{-34}}{620 \times 10^{-9}} \] - Calculate the resulting momentum. This problem demonstrates the application of fundamental physics equations to determine the properties of photons, fundamental particles of light. These calculations are pivotal in quantum mechanics, optics, and various applications in physics and engineering.
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