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Calculate the following energies:
the kinetic energy of a lead K-shell photoelectron following a photoelectric interaction of a 662
keV gamma ray (K-shell binding energy of Pb = 88 keV).

Expert Solution

Step 1

Given:

The energy of the incident gamma ray is $E = 662 keV$

The binding energy of an electron in the K-shell is $ϕ = 88 keV$

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