Exhibit 13-21 Sum of Squares Between Groups (Treatment) 6,000.0 Within Groups (Error) Source of Variation Total Degrees of Freedom 5 24 29 The population proportion are all the same The row and column variables are independent Mean Square The population means are all equal. At least on of the population means is different 1,200 288 Refer to Exhibit 13-21. What is the correct null hypothesis in this problem? F

Exhibit 13-21 Sum of Squares Between Groups (Treatment) 6,000.0 Within Groups (Error) Source of Variation Total Degrees of Freedom 5 24 29 The population proportion are all the same The row and column variables are independent Mean Square The population means are all equal. At least on of the population means is different 1,200 288 Refer to Exhibit 13-21. What is the correct null hypothesis in this problem? F

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Source of Variation Sum of Squares (SS) df Mean Square (MS) F Treatments 11 2 ? ? Error ? ? ? Total 39 19 Refer to the Table. What are the degrees of freedom for the Errors? Select one: a. 12 b. 17 c. 3 d. 4
Marathon start-up years 2010 When we considered theBoston Marathon in Exercise 37, we were unable tocheck the Nearly Normal Condition. Here’s a histogramof the differences:Those three large differences are the first three years ofwheelchair competition: 1977, 1978, and 1979. Often thestart-up years of new events are different; later on, moreathletes train and compete. If we omit those three years,the summary statistics change as follows:Summary of wheelchrF - runMN = 31Mean = -12.794SD = 18.64a) Comment on the assumptions and conditions.b) Assuming that these times are representativeof such races, construct and interpret a 95%confidence interval for the mean difference infinishing time.c) Would a hypothesis test at a = 0.05 reject the nullhypothesis of no difference? What conclusion wouldyou draw?
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Coffee and blood pressure. A scientist suspects that coffee increases blood pressure. So, he measures the systolic blood pressure of six random patients and then measures it again 30 minutes after they drink a single cup of caffeinated coffee. The results are tabulated below. Test the claim that coffee causes an increase in blood pressure. Before Coffee 123 114 100 120 112 115 After Coffee 123 119 102 121 112 118 (a) Why are these paired data? O This table does not have paired data; there is no clear relationship between the data in each column. O Each column contains data from the same patient. O Most of the 'After Coffee' values are smaller than the corresponding 'Before Coffee' values. O The after and before rows are the same size. (b) Write the hypotheses in symbols. Note that this problem uses Haiffabefore-after instead of Pdiff-after-before so be careful. O H;: Pdiffabefore-after = 0 H3: Pdiff-before-after 0 O Ho: Hdiffabefore-after H3: Pdiffabefore-after = 0 = 0 OH,:…
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You are conducting a test of homogeneity for the claim that two different populations have the same proportions of the following two characteristics. Here is the sample data. Population Population Category # 1 # 2 22 69 B 44 109 What is the chi-square test-statistic for this data? Report all answers accurate to three decimal places.
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If you calculate an F statistic and find that it is negative, then you know that: Question 29 options: the difference among the group means is less than what would have occurred by chance the within-groups variance exceeds the between-groups variance you have made a calculation error the difference among the group means is greater than what would have occurred by chance
Exhibit 13-21 Source of Variation Between Groups (Treatment) 6,000.0 Within Groups (Error) Total 51 29 Sum of Squares 32 30 Degrees of Freedom 5 24 29 Mean Square Refer to Exhibit 13-21. The sample size in this problem is? (Hint: Use the fact that the total degrees of freedom - n-1) 1,200 288 F
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Exhibit 10-16 The following is part of an ANOVA table, which was the results of three treatments and a total of 15 observations. Source of Variation Between Treatments Within Treatments (Error) Total Sum of Squares 64 96 Degrees of Freedom Mean Square F Refer to Exhibit 10-16. The number of degrees of freedom corresponding to between treatments is