Exhibit 13-21 Source of Variation Between Groups (Treatment) 6,000.0 Within Groups (Error) Total OSI 29 Sum of Squares 32 30 Degrees of Freedom 5 24 29 Mean Square Refer to Exhibit 13-21. The sample size in this problem is? (Hint: Use the fact that the total degrees of freedom- n-1) 1,200 288 F
Exhibit 13-21 Source of Variation Between Groups (Treatment) 6,000.0 Within Groups (Error) Total OSI 29 Sum of Squares 32 30 Degrees of Freedom 5 24 29 Mean Square Refer to Exhibit 13-21. The sample size in this problem is? (Hint: Use the fact that the total degrees of freedom- n-1) 1,200 288 F
MATLAB: An Introduction with Applications
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Transcribed Image Text:**Exhibit 13-21**
| Source of Variation | Sum of Squares | Degrees of Freedom | Mean Square |
|-------------------------|----------------|--------------------|-------------|
| Between Groups (Treatment) | 6,000.0 | 5 | 1,200 |
| Within Groups (Error) | 24 | 288 | |
| **Total** | | 29 | |
Refer to Exhibit 13-21. The sample size in this problem is? (Hint: Use the fact that the total degrees of freedom = n-1)
- ○ 51
- ○ 29
- ○ 32
- ○ 30
**Explanation:**
In this table, the analysis of variance (ANOVA) is presented. It includes the following components:
1. **Between Groups (Treatment):** This measures the variation attributed to the differences between groups. It has a Sum of Squares of 6,000.0, with 5 degrees of freedom, leading to a Mean Square of 1,200.
2. **Within Groups (Error):** This measures the variation within each group. It has a sum of squares of 24 and a total of 288 degrees of freedom.
3. **Total:** The combined degrees of freedom across the entire analysis is 29.
**Calculating Sample Size:**
To find the sample size (n), remember that the total degrees of freedom is calculated as n-1. Given that the total degrees of freedom is 29, the sample size will be \( n = 29 + 1 = 30 \). Therefore, the correct answer is 30.
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