Exercises 245 6.45 When solutions containing silver ions and chloride ions are mixed, silver chloride precipitates iner neat nich Ag*(aq) + Cl¯(aq) AgCl(s) AH = ДН %3 -65.5 kJ (1) to r to (a) Calculate AH for the production of 0.450 mol of AgCl by this reaction. (b) Calculate AH for the production of 9.00 g of AgCl. (c) Calculate AH when 9.25 x 10-4 mol of AgCl dis- DUA solves in water. ric es 6.46 At one time, a common means of forming small quantities of oxygen gas in the laboratory was to heat KCIO3: 2 KCIO3(s) → 2 KC1(s) + 3 O2(g) AH= -89.4 kJ %3D For this reaction, calculate AH for the formation of (a) 1.36 mol

Exercises 245 6.45 When solutions containing silver ions and chloride ions are mixed, silver chloride precipitates iner neat nich Ag*(aq) + Cl¯(aq) AgCl(s) AH = ДН %3 -65.5 kJ (1) to r to (a) Calculate AH for the production of 0.450 mol of AgCl by this reaction. (b) Calculate AH for the production of 9.00 g of AgCl. (c) Calculate AH when 9.25 x 10-4 mol of AgCl dis- DUA solves in water. ric es 6.46 At one time, a common means of forming small quantities of oxygen gas in the laboratory was to heat KCIO3: 2 KCIO3(s) → 2 KC1(s) + 3 O2(g) AH= -89.4 kJ %3D For this reaction, calculate AH for the formation of (a) 1.36 mol

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question 15.62
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2. Lead (II) sulfide is the principle source of lead metal. To obtain the metal, the sulfide is first heated in air to produce PbO. PbS + 3/20,e - PbO + SO2) AH = -415.4 kJ (s) (8)7 The oxide is then reduced to the metal with carbon. PbO + C - Pb + CO (s) Calculate AH for the reaction of one mole of PbS with oxygen and carbon, forming lead, sulfur AH =+108,5 kJ (s) dioxide and carbon monoxide.