LIOh foreach substance in Appendix C: (a) H2O2(g), (b) CaCO3(s),and then 1OUR upnewtionany,(c) РОСІ: (1), (а) СH;ОН().6.71 The following is known as the thermite reaction:2 Al(s) + Fe,O3(s) → Al2O3(s) + 2 Fe(s)This highly exothermic reaction is used for welding massiveunits, such as propellers for large ships. Using standard en-thalpies of formation in Appendix C, calculate AH° for thisereaction.cou

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Answered: LIOh for each substance in Appendix C:…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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5. Reaction Enthalpy. balance and calculate AHxn for the following chemical equations. AH (kJ/mol): HCN= 130.5, Ca3(PO4)2=-4120.8, H3PO4--1288, SiCl4=-640.1, SiO2= -910.9, Mg0=-601.6, HCl--167.16 a)NH₂(g) + O₂(g) + CH CH4(g) b)Ca₂(PO4)2(6) +H₂SO4(1) c)SICI(1) + H₂0 (1) d) MgO(s)+ H₂ H₂O(g) SIO₂ (s) + HCN HCN(g) + Caso (s) + H₂PO.(1) Mg(OH)2(s) H₂O(g) HCl(aq)
Consider the reaction of a mixture of NaHCO3 and Ca(HCO3)2 with excess HCl. The net ionic reaction observed is H+(aq) + HCO3-(aq) → H2O(l) + CO2(g) The data for this problem is for 25 oC 7.701 g of a sample containing a mixture of NaHCO3 and Ca(HCO3)2 is mixed with an excess of HCl to produce CO2 gas. When all of the (dried) gas is collected in a 1.00 L vessel, the total pressure is 1.452 atm. How many g of NaHCO3 were present in the initial sample?
Calculate AH for the reaction of sulfur dioxide with oxygen. 2SO2 (g) + O2 (g) –→ 2SO3 (g) (AHf ° SO2 (g) = -296.8 kJ/mol; AHf ° SO3 (g) = -395.7 kJ/mol) Select one: O a. -98.9 kJ O b. -197.8 kJ O c. Not enough information is given. O d. 197.8 kJ
1.4 4 (a) Calculate the value of Kc for the reaction: PCl5 (g) PCl3 (g) + Cl2 (g) ΔH = Positive Given that when 8.4 mol of PCl5 (g) is mixed with 1.8 mol of PCl3 (g) and allowed to come to equilibrium in a 10 dm3container the amount of PCl5 (g) at equilibrium is 7.2 mol. Kc =
There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In the first step, calcium carbide (CaC,) and water react to form acetylene (C,H,) and calcium hydroxide: CaC, (s) + 2H,0(g) - C,H,(g) + Ca(OH), (s) In the second step, acetylene (C,H,), carbon dioxide and water react to form acrylic acid (CH,CHCO,H): 6C,H, (g) 3co,(g) + 4H,0(g) 5 CH, CHCO,H (g) Suppose the yield of the first step is 68.% and the yield of the second step is 66.%. Calculate the mass of calcium carbide required to make 10.0 kg of acrylic acid. Be sure your answer has a unit symbol, if needed, and is rounded to the correct number of significant digits.
Under certain nonstandard conditions, oxidation by O2( g) of1 mol of SO2( g) to SO3( g) absorbs 89.5 kJ. The enthalpy of formationof SO3( g) is -204.2 kJ under these conditions. Find theenthalpy of formation of SO2( g).
uestion 27 "A new element (Rr) has been synthesized and its properties analyzed. When 0.157g of RrO (s) is added to 125g of water at 22.2° C in a coffee cup calorimeter, the following reaction occurs. RrO(s) + H 20(1) – Rr(OH) 2 (aq) AH = -83.1k/mol Given the molar mass for RrO is 74g/mol calculate the following moles of Rro round answer to 4 decimal places omit trailing zeroes 9 rxn in joules round answer to the nearest whole number 9 water in joules round answer to the nearest whole number Final temperature round answer to 1 decimal place omit trailing zeroes " A Moving to another question will save this response.
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5. Reaction Enthalpy. balance and calculate AH for the following chemical equations. AH (kJ/mol): HCN = 130.5, Ca3(PO4)2=-4120.8, H3PO4-1288, SiCl₁=-640.1, SiO₂= -910.9, Mg0=-601.6, HCl=-167.16 d) Mg(s) + H₂0(g) 0 Mg(OH)2(s)
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Given the reaction 2 CO CO2(g) What is AHO of this reaction? AHO CO (g) = -111 kJ/mol ΔΗ° 2H2 (g) = 0 kJ/mol AHO CH4(g) =-75 kJ/mol AHO CO2(g) = = -393.5 kJ/mol O c) 357 Ob) -357 Od) -246,5 (g) + 2H2(g) → CH4(g) + O a) 579
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