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Exercises 13-15 prove the three possible cases of Theorem 9-8. In each case you are given chord TA and tangent TP of 0. 13. Supply reasons for the key steps of the proof that IMANT in Case I. A m LATP = Case I: O lies on ZATP. 1. TP 1 TA and m LATP = 90. 2. ANT is a semicircle and MANT = 180. 3. m LATP = IMÁNT T.

Exercises 13-15 prove the three possible cases of Theorem 9-8. In each case you are given chord TA and tangent TP of 0. 13. Supply reasons for the key steps of the proof that IMANT in Case I. A m LATP = Case I: O lies on ZATP. 1. TP 1 TA and m LATP = 90. 2. ANT is a semicircle and MANT = 180. 3. m LATP = IMÁNT T.

Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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Exercises 13-15 prove the three possible cases of Theorem 9-8. In each case you are given chord TA and tangent TP of 0. 13. Supply reasons for the key steps of the proof that IMANT in Case I. A m LATP = Case I: O lies on ZATP. 1. TP 1 TA and m LATP = 90. 2. ANT is a semicircle and MANT = 180. 3. m LATP = IMÁNT T.
Transcribed Image Text:Exercises 13-15 prove the three possible cases of Theorem 9-8. In each case you are given chord TA and tangent TP of 0. 13. Supply reasons for the key steps of the proof that IMANT in Case I. A m LATP = Case I: O lies on ZATP. 1. TP 1 TA and m LATP = 90. 2. ANT is a semicircle and MANT = 180. 3. m LATP = IMÁNT T.
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