Suppose line L connects points Q and R and suppose point P is not on L. Let point S be the unique point on L such that line PS is perpendicular to L. Then b=QP. Now consider right triangle PQS formed by QP, PS, QS. By the properties of right triangles, sin(8) b) sin(8). d= w Since 8 is the angle between b and a, by the given theorem sin(8) d= [b] sin(0) - b la x bl al b v as was to be shown. Jax bl la) la x b la cos(8) Thus, ) Use the formula in part (a) to find the distance from the point P(1, 1, 1) to the line through Q(0, 9, 6) and R(-1, 3, 6). -d is the maximum distance from point P to line L. Let a QR and

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