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Exercise#6: The current through a 250-mH inductor takes the following values. Calculate he expression for the voltage across the inductor in each case. a. i̟(t) = 5 sin 25t A p. i(t) =- 10 cos 50t A E. i̟(t) = 25 cos(100t + TT/3) A 1. i̟(t) = 20 sin(10t – T/12) A

Exercise#6: The current through a 250-mH inductor takes the following values. Calculate he expression for the voltage across the inductor in each case. a. i̟(t) = 5 sin 25t A p. i(t) =- 10 cos 50t A E. i̟(t) = 25 cos(100t + TT/3) A 1. i̟(t) = 20 sin(10t – T/12) A

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Exercise#6: The current through a 250-mH inductor takes the following values. Calculate the expression for the voltage across the inductor in each case. a. i (t) = 5 sin 25t A b. i̟(t) : c. i (t) = 25 cos(100t + TT/3) A d. i (t) = 20 sin(10t – /12) A =-10 cos 50t A
Transcribed Image Text:Exercise#6: The current through a 250-mH inductor takes the following values. Calculate the expression for the voltage across the inductor in each case. a. i (t) = 5 sin 25t A b. i̟(t) : c. i (t) = 25 cos(100t + TT/3) A d. i (t) = 20 sin(10t – /12) A =-10 cos 50t A
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