A 0.185 H inductor is connected in series with a 86 2 resistor and an ac source. The voltage across the inductor is VL = -(13.0V) sin[(480rad/s)t]. %3D

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A 0.185 HI inductor is connected in series with a 86 22 resistor and an ac source. The voltage across the inductor is UI = - (13.0V) sin| (480rad/s)t]. Please answer both parts A and B with appropriate units.
A 0.185 H inductor is connected in series with a 86 2 resistor
and an ac source. The voltage across the inductor is
VL = -(13.0V) sin[(480rad/s)t].
%3D
Transcribed Image Text:A 0.185 H inductor is connected in series with a 86 2 resistor and an ac source. The voltage across the inductor is VL = -(13.0V) sin[(480rad/s)t]. %3D
I Review
Part A
Derive an expression for the voltage vR across the resistor.
Express your answer in terms of the variables L, R, VL (amplitude of the voltage across the inductor), w, and t.
VR =
Part B
What is vR at 1.89 ms?
Express your answer with the appropriate units.
HA
VR =
Value
Units
Transcribed Image Text:I Review Part A Derive an expression for the voltage vR across the resistor. Express your answer in terms of the variables L, R, VL (amplitude of the voltage across the inductor), w, and t. VR = Part B What is vR at 1.89 ms? Express your answer with the appropriate units. HA VR = Value Units
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