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A student wraps 100 turns of wire on a pencil that is 7 mm in diameter as shown in Figure 13-46. The pencil is a nonmagnetic core so has the same permittivity as a vacuum (4x E-6 H/m). Determine the inductance of the coil that is formed. L = N² u A/

A student wraps 100 turns of wire on a pencil that is 7 mm in diameter as shown in Figure 13-46. The pencil is a nonmagnetic core so has the same permittivity as a vacuum (4x E-6 H/m). Determine the inductance of the coil that is formed. L = N² u A/

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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**Problem Statement:** A student wraps 100 turns of wire on a pencil that is 7 mm in diameter as shown in Figure 13-46. The pencil is a nonmagnetic core and therefore has the same permittivity as a vacuum (4π x 10^-6 H/m). Determine the inductance of the coil that is formed. **Formula Provided:** \[ L = \frac{N^2 \cdot \mu \cdot A}{l} \] Where: - \( N \) is the number of turns. - \( \mu \) is the permeability of the core material. - \( A \) is the cross-sectional area. - \( l \) is the length of the coil. **Explanation of Graphs or Diagrams:** There are no graphs or diagrams provided in the image for further explanation.
Transcribed Image Text:**Problem Statement:** A student wraps 100 turns of wire on a pencil that is 7 mm in diameter as shown in Figure 13-46. The pencil is a nonmagnetic core and therefore has the same permittivity as a vacuum (4π x 10^-6 H/m). Determine the inductance of the coil that is formed. **Formula Provided:** \[ L = \frac{N^2 \cdot \mu \cdot A}{l} \] Where: - \( N \) is the number of turns. - \( \mu \) is the permeability of the core material. - \( A \) is the cross-sectional area. - \( l \) is the length of the coil. **Explanation of Graphs or Diagrams:** There are no graphs or diagrams provided in the image for further explanation.
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