Exercise 19.59 Enhanced with Feedback MISSED THIS? Watch IWE Calculating Standard Entropy Changes (AS rxn). Read Section 19.7. You can click on the Review link to access the section in your e Text. Substance S° (J/(mol-K)) 5.7 2.4 C(s, graphite) C(s, diamond) H(g) H₂(g) Cl(g) Cl₂(g) CH₂Cl2 (g) ▬▬ 114.7 130.7 165.2 223.1 270.2 Part A Find A.Sº for the formation of CH₂Cl₂ (g) from its elements in their standard states. Express your answer in joules per kelvin to one decimal place. ASin = Submit IVΞΙ ΑΣΦ Request Answer Part B Complete previous part(s) ? J/K 7 of 23 Review | Constants | Periodic Table

Exercise 19.59 Enhanced with Feedback MISSED THIS? Watch IWE Calculating Standard Entropy Changes (AS rxn). Read Section 19.7. You can click on the Review link to access the section in your e Text. Substance S° (J/(mol-K)) 5.7 2.4 C(s, graphite) C(s, diamond) H(g) H₂(g) Cl(g) Cl₂(g) CH₂Cl2 (g) ▬▬ 114.7 130.7 165.2 223.1 270.2 Part A Find A.Sº for the formation of CH₂Cl₂ (g) from its elements in their standard states. Express your answer in joules per kelvin to one decimal place. ASin = Submit IVΞΙ ΑΣΦ Request Answer Part B Complete previous part(s) ? J/K 7 of 23 Review | Constants | Periodic Table

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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W ↑ To determine the spontaneity of a chemical reaction, the sign of AG rather than the sign of AS is generally used. This is because O (1) AG is always positive and AS may be positive or negative O (2) Free energy free and it is easier to understand than entropy. O (3) AG is always larger than AS O (4) none given #3 3 A Moving to the next question prevents changes to this answer. E C $ 4 D R G Search or type URL % 5 MacBook Pro T (O G Y & 7 H U * 8 J 9 K 0 1 L Questi P
Determine if the decomposition of potassium chlorate (KClO3) is spontaneous or not. 2 KClO3(s) > 2 KCl(s) + 3 O2(g) Substance KClO3(s) KCl(s) O2(g) S° (J/mol-K) 143.1 82.6 205.0 H° (J/mol-K) -397700 -436700 0 Answer the following: Entropy of system Enthalpy Entropy of surrounding Entropy of universe Spontaneity
18.29 The enthalpy change when liquid methanol , CH 3 OH , vaporizes at 25 degrees * C is 37.4kJ / m * o * l . What is the entropy change when 1.50 mol of vapor in equilibrium with liquid condenses to liquid at 25° C? The entropy of the vapor at 25 degrees * C is 252 J (molK) What is the entropy of the liquid at this temperature ?
Entropy Changes (AS rxn) ; Read Section 19.7. You can click on the Review link to access the section in your e Text. Substance S° (J/(mol. K)) 5.7 2.4 C(s, graphite) C(s, diamond) H(g) H₂(g) Cl(g) Cl₂ (g) CH3 Cl(g) 114.7 130.7 165.2 223.1 234.6 Find AS for the formation of CH3C1(g) from its elements in their standard states. Express your answer in joules per kelvin to one decimal place. ΠΟΠΗ ΑΣΦ ASixn= - Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining 1 ? J/K
Determine if the formation of acid rain is a spontaneous reaction at 50°C Chemical Equation: NO2 + H2O → HNO2 + HNO3 Compound ΔH° (kJ/mol) ΔS° (J/K•mol) NO2 33.85 240.46 H2O –285.8 69.9 HNO2 –118.8 254.1 HNO3 –173.2 155.6 Compute for the ΔS° rxn ( J/K•mol) of the equation: _________ (round off final answer to 1 decimal place)
Determine the entropy change in each of the following processes: 4a. One mole of an ideal gas is allowed to expand from a volume of 1.50 L to 15.0 L at 298 K. 4b. 10 grams of methanol vapor, initially at its normal boiling temperature of 337 K, is allowed to condense and cool to a liquid at a final temperature of 298 K.
6 points Save Answer Question 11 Will entropy increase or decrease for each of the following processes? burming coal C6H1206 (s) + 602 (g) → 6CO2 (g) + 6H20 (1) Tossing a salad
question will save this response. Question 17 Using the entropy values in the table below, what is the change in standard entropy, ASº, for the following reaction? 2 CH3OH (1)+3 02 (g)→2 CO2 (g) + 4 H2O (g) Substance S° (J/mol K) CH3OH (1) CH3OH (g) 02 (g) CO2 (g) H2O (g) 127 238 205 214 189 H20 (1) 240 J/K 70 93 J/K 315 J/K -161 J/K O-383 J/K A Moving to another question will save this response. MacBook Air 30 Qa F4 F5 F3 F1 F2 % %24
Part A Calculate the standard change in entropy for the reaction. 2 NH3(g) + 2O2(g) → N₂O(g) + 3 H₂O(g) ► View Available Hint(s) O -9.6 J/K O 811.2 J/K O 10.8 J/K
When a reaction is exothermic and the products have more entropy than the reactants, the reaction is? Choose the right answer in the given choices below: a.) Spontaneous, with a negative ΔG b.) Non-spontaneous, with a negative ΔG c.) Spontaneous, with a positive ΔG d.) Non-spontaneous, with a positive ΔG
Thermodynamics For Practice 18.6 Enhanced - with Feedback Part A Consider the oxidation of SO2 to SO3 : SO2(g)+,O2(g)→SO3(9) Calculate AGxn at 25° C. IXI Express your answer with the appropriate units. ΔΗ (kJ/mol) Reactant or S° product (J/mol · K) SO2 -296.8 248.2 O2 205.2 SO3 -395.7 256.8 AGn Value Units You may want to reference (Pages 820 - 826) Section 18.8 while completing this problem.
For the reaction C(s) + H2O(g) → CO(g) + H2(g) ΔH° = 131.3 kJ/mol and ΔS° = 127.6 J/K ∙ mol at 298 K. At temperatures greater than __________°C this reaction is spontaneous under standard conditions. A) 273 B) 325 C) 552 D) 756 E) 1029