Predict the sign of the standard entropy change for each of the following: PC13(g) → PC13 (1) AS is AS is -= 11 2 KCl(s) → 2 K(s) + Cl₂(g) 2+ Ca²+ (aq) + CO3(aq) → CaCO3(s)

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Chapter1: Chemical Foundations
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**Question 2**

Predict the sign of the standard entropy change for each of the following:

1. \( \text{PCl}_3(g) \rightarrow \text{PCl}_3(l) \)

   \( \Delta S^\circ \) is [ -- ]

2. \( 2 \text{KCl}(s) \rightarrow 2 \text{K}(s) + \text{Cl}_2(g) \)

   \( \Delta S^\circ \) is [ -- ]

3. \( \text{Ca}^{2+}(aq) + \text{CO}_3^{2-}(aq) \rightarrow \text{CaCO}_3(s) \)

   \( \Delta S^\circ \) is [ -- ]
Transcribed Image Text:**Question 2** Predict the sign of the standard entropy change for each of the following: 1. \( \text{PCl}_3(g) \rightarrow \text{PCl}_3(l) \) \( \Delta S^\circ \) is [ -- ] 2. \( 2 \text{KCl}(s) \rightarrow 2 \text{K}(s) + \text{Cl}_2(g) \) \( \Delta S^\circ \) is [ -- ] 3. \( \text{Ca}^{2+}(aq) + \text{CO}_3^{2-}(aq) \rightarrow \text{CaCO}_3(s) \) \( \Delta S^\circ \) is [ -- ]
Expert Solution
Step 1

For PCl3 (g)  PCl3 (l)

Entropy decreases, so, the sign will be negative.

 

For 2 KCl (s)  2K (s) + Cl2(g)

Here, Cl2 gas is evolved. So, entropy increases. 

Hence, the sign will be positive.

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