a) For the vaporization of a liquid at its boiling point, A(l) → A(g), is the entropy change of the universe negative, positive, or zero? b)For the vaporization of a liquid at its boiling point, A(l) → A(g), is the entropy change of the system negative, positive, or zero? c)For the vaporization of a liquid at its boiling point, A(l) → A(g), is the entropy change of the surroundings/environment negative, positive, or zero?
a) For the vaporization of a liquid at its boiling point, A(l) → A(g), is the entropy change of the universe negative, positive, or zero?
b)For the vaporization of a liquid at its boiling point, A(l) → A(g), is the entropy change of the system negative, positive, or zero?
c)For the vaporization of a liquid at its boiling point, A(l) → A(g), is the entropy change of the surroundings/environment negative, positive, or zero?
The entropy tells the randomness present in the system due to its disorderness created in the system as the temperature is raised.
Gaseous molecules have higher entropy as compared to liquid which is turn has higher entropy as compared to solid.
If the number of gaseous molecules on the product side are more as compared to reactants than the entropy of the reaction increases.
If the number of gaseous molecules on the reactant side are more as compared to the product than the entropy of the reaction will decrease.
a.
The entropy of the universe always increases thus, for the vaporization of the liquid at its boiling point the entropy of the universe is positive.
b.
As the aluminium is converting from liquid to gas at its boiling point that means the disorderness is increasing thus, the entropy of the system is positive.
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