Activity 3. Gibbs Free Energy (LAS 5.a) Learning Objective: Solve problems involving the standard Gibbs free energy. Substance AG° (kJ/mol) What you need: Pen, Paper, Periodic Table of Elements and Calculator. CH4 -50.8 What to do: Calculate the standard free-energy changes for the following eactions at 25°C and interpret the values obtained from the calculations. Write your answers in a separate sheet of paper. 02 CO2 -394.4 1. CHa(g) + 202(g) → CO2(g) + 2H2O(1) H20 -237.2 2. 2M9O(s) → 2Mg(s) + O2(g) Mgo -569.6 Mg

Activity 3. Gibbs Free Energy (LAS 5.a) Learning Objective: Solve problems involving the standard Gibbs free energy. Substance AG° (kJ/mol) What you need: Pen, Paper, Periodic Table of Elements and Calculator. CH4 -50.8 What to do: Calculate the standard free-energy changes for the following eactions at 25°C and interpret the values obtained from the calculations. Write your answers in a separate sheet of paper. 02 CO2 -394.4 1. CHa(g) + 202(g) → CO2(g) + 2H2O(1) H20 -237.2 2. 2M9O(s) → 2Mg(s) + O2(g) Mgo -569.6 Mg

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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The reaction 2N20(g) 2N2(3) + O2(g) has AH° = -163.14 kJ. What is the value of AE for the decomposition of 112 g of N20 at 25 °C? If we assume that AH doesn't change appreciably with temperature, what is AE for this reaction at 296 °C? At 25 C: ΔΕ i kJ At 296 °C: AE = i kJ
Consider the reaction described by the chemical equation shown. C,H,(g) + H,O(1) – C,H,OH(1) AH xn = -44.2 kJ Use the data from the table of thermodynamic properties to calculate the value of ASxn at 25.0 °C. ASixn J.K-! Calculate AGixn ·
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Predict the sign of ASº, +, -, or 0, for each of the following reactions and drag it into the boxes: • Lead nitrate (Pb(NO3)2) and potassium iodide (KI) solutions form a precipitate of lead iodide (Pbl2) when mixed • Ice melts at 0°C 0 • Magnesium metal reacts with oxygen gas to form solid magnesium oxide ● Hydrogen gas (H₂) and chlorine gas (Cl₂) react to form hydrochloric gas (HCI) gas + O
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Be sure to answer all parts. For the gaseous reaction of carbon monoxide and chlorine to form phosgene (COCl₂), perform the following calculations. (a) Calculate the AS at 298 K (AH° = −220. kJ/mol and AG° = −206 kJ/mol). kJ/mol K (b) Assuming that AS and AH change little with temperature, calculate AG at 450. K. kJ/mol
8. Note: Please don't write on a paper, I can't understand handwrittens.
1.) Complete A and B to move on. a.) Write the complete, balanced chemical equation for the following reaction on a separate sheet of paper. Provide products where they are not given. Assume that the reaction is spontaneous. Propane (C3H8) + oxygen → carbon dioxide + water Type the sum of the coefficients in the equation into the answer blank. If there is no coefficient, count it as one. Include ( g, s, l, or aq) b.) Write the complete, balanced chemical equation for the following reaction on a separate sheet of paper. Provide products where they are not given. Assume that the reaction is spontaneous. Diphosphorus pentoxide + water → Type in the coefficient and formula for the product in the equation that contains phosphorus. Include ( g, s, l, or aq)
Identify the reactions that are exothermic. ) Multiple answers: Multiple answers are accepted for this question Select one or more answers and submit. For keyboard navigation... SHOW MORE V C(graphite)C(diamond) AH° = 2 kJ b. CaCO3 (s) CaO(s) + CO2(g) AH° = 178 kJ CuO(s) + H2 (g) → Cu(s) + H2 0(g) AH° = -85 kJ 2H2 (g) + 02(g) - 2H20(g) AH = -484 kJ 3H2 (g) + N2(g) 2NH3 (g) AH - 92 kJ Unanswered
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Using H° data, calculate the standard enthalpy change for the reaction at 298K. 2 NH3(g) HNO3(aq) --> NO2(g) 2 H20(1) AH° (KJ/mol) -46.19 -206.6 33.84 -285.83 (Note: the table AH values are located directly below the corresponding compound, this is the number found in the Appendix)
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