Exercise 10.14: "Joint deductions Let X and Y be discrete random variables with probability mass functions given by Ik 0 1 and Furthermore assume that = P(X k) 1/2 1/2 Ye 0 1 2 P(Y ye) 1/3 1/3 1/3 P(X =0,Y=0) = P(X = 1, Y = 2) = 0. Find the joint probability mass function of X and Y.
Exercise 10.14: "Joint deductions Let X and Y be discrete random variables with probability mass functions given by Ik 0 1 and Furthermore assume that = P(X k) 1/2 1/2 Ye 0 1 2 P(Y ye) 1/3 1/3 1/3 P(X =0,Y=0) = P(X = 1, Y = 2) = 0. Find the joint probability mass function of X and Y.
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
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
Transcribed Image Text:Exercise 10.14: "Joint deductions
Let X and Y be discrete random variables with probability mass functions given by
Ik 0 1
and
Furthermore assume that
=
P(X k) 1/2 1/2
Ye 0
1
2
P(Y ye) 1/3 1/3 1/3
P(X =0,Y=0) = P(X = 1, Y = 2) = 0.
Find the joint probability mass function of X and Y.
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