A random variable X has the following probability mass function: -1 0 1 1/4 1/5 X -2 P(X=x) Let Y be a new random variable defined by Y = (a) List the values Y takes. (b) Find the probability mass function of Y. 1/10 2/5 X² + 4. 2 1/20

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A: The probability mass function for the X can be defined as:

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Q: 5/1/24, 11:52 PM A L Solve the problem. 17) The accompanying table shows the probability…

A: xP(x)x*P(x)x2*P(x)10.10.10.120.220.440.8830.160.481.4440.10.41.650.170.854.2560.251.59…

Q: = 1- Q(x).

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