1. The discrete random variables X and Y have known joint probability mass function [c x=0,1,2,L,9, y=0,1,2,L,9, yzx otherwise , where c = 1/55. 0 Pxy(x, y) given by Py(x, y) = Define the event B = {X² + y² ≤25}. a) Determine the conditional PMF P(x, y/B) of the random variables X and Y. b) Determine the conditional marginal PMFs P(x/B) and P(y/B) of the random variables X and Y. c) Determine the conditional correlation E{XY/B} of the random variables X and Y. (Take advantage of the solutions to Prob. 1 in Homework #8.)

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1. The discrete random variables \(X\) and \(Y\) have known joint probability mass function \( P_{XY}(x, y) \) given by

\[
P_{XY}(x, y) = 
\begin{cases} 
c & x = 0, 1, 2, L, \ 9, \ y = 0, 1, 2, L, \ 9, \ y \geq x \\ 
0 & \text{otherwise} 
\end{cases}
\]

where \( c = 1/55 \).

Define the event \( B = \{ X^2 + Y^2 \leq 25 \} \).

a) Determine the conditional PMF \( P_{XY}(x, y / B) \) of the random variables \(X\) and \(Y\).

b) Determine the conditional marginal PMFs \( P_X(x / B) \) and \( P_Y(y / B) \) of the random variables \(X\) and \(Y\).

c) Determine the conditional correlation and \( E\{XY / B\} \) of the random variables \(X\) and \(Y\).

(Take advantage of the solutions to Prob. 1 in Homework #8.)

Solution for [Homework 8](#) is COV(\(X,Y\))=3, correlation = \(1/2\), not statistically independent.
Transcribed Image Text:1. The discrete random variables \(X\) and \(Y\) have known joint probability mass function \( P_{XY}(x, y) \) given by \[ P_{XY}(x, y) = \begin{cases} c & x = 0, 1, 2, L, \ 9, \ y = 0, 1, 2, L, \ 9, \ y \geq x \\ 0 & \text{otherwise} \end{cases} \] where \( c = 1/55 \). Define the event \( B = \{ X^2 + Y^2 \leq 25 \} \). a) Determine the conditional PMF \( P_{XY}(x, y / B) \) of the random variables \(X\) and \(Y\). b) Determine the conditional marginal PMFs \( P_X(x / B) \) and \( P_Y(y / B) \) of the random variables \(X\) and \(Y\). c) Determine the conditional correlation and \( E\{XY / B\} \) of the random variables \(X\) and \(Y\). (Take advantage of the solutions to Prob. 1 in Homework #8.) Solution for [Homework 8](#) is COV(\(X,Y\))=3, correlation = \(1/2\), not statistically independent.
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