Exercise 1. Two different companies have applied to provide cable television servicein a certain region. Let p denote the proportion of all potential subscribers who favorthe first company over the second. Consider testing Hop .5 versus H₁ : p ‡ .5based on a random sample of 25 individuals. Let the test statistic X be the numberin the sample who favor the first company and x represent the observed value of x=If the test rejects Ho if x ≥ 15 or x ≤ 10. Compute the probability of type I error.

Type I error: Reject the null hypothesis when it is true. Here, it can be concluded that a majority…

Answered: Exercise 1. Two different companies…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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A physical therapist wanted to know whether the mean step pulse of men was less than the mean step pulse of women. She randomly selected 54 men and 70 women to participate in the study. Each subject was required to step up and down a 6-inch platform. The pulse of each subject was then recorded. The following results were obtained. Two sample T for Men vs Women N Mean StDev SE Mean Men Women 98% CI for mu Men - mu Women (- 12.20, - 1.00) T-Test mu Men = mu Women (vs H2 O C. Ho: H1 = H2; Ha: H1 #H2 (b) Identify the P-value and state the researcher's conclusion if the level of significance was a = 0.01. What is the P-value? P-value =
A study of parental empathy for sensitivity cues and baby temperament (higher scores mean more empathy) was performed. Let x1 be a random variable that represents the score of a mother on an empathy test (as regards her baby). Let x2 be the empathy score of a father. A random sample of 40 mothers gave a sample mean of x1 = 68.36. Another random sample of 36 fathers gave x2 = 57.34. Assume that ?1 = 11.83 and ?2 = 11.72. (a)Let ?1 be the population mean of x1 and let ?2 be the population mean of x2. Find a 99% confidence interval for ?1 – ?2. (Round your answers to two decimal places.) lower limit=__ upper limit=__
Suppose IQ scores were obtained for 20 randomly selected sets of twins. The 20 pairs of measurements yield x=98.34, y=100.45, r=0.940, P-value=0.000, and y=−3.86+1.06x, where x represents the IQ score of the twin born second. Find the best-predicted value of y given that the twin born second has an IQ of 103? Use a significance level of 0.05.
Suppose IQ scores were obtained for 20 randomly selected sets of twins. The 20 pairs of measurements yield x= 99.11, y = 100.1, r=0.872, P-value = 0.000, and y = 7.99 +0.93x, where x represents the IQ score of the twin bom first. Find the best predicted value of y given that the twin born first has an IQ of 96? Use a significance level of 0.05. 1 Critical Values of the Pearson Correlation Coefficient r E Click the icon to view the critical values of the Pearson correlation coefficient r. The best predicted value of y is. Critical Values of the Pearson Correlation Coefficient r a = 0.01 NOTE: To test Ho: p=0 against H,: p#0, reject H, if the absolute value of r is greater than the critical value in the table. (Round to two decimal places as needed.) a = 0.05 4 0.950 0.990 0.878 0.959 0.811 0.917 0.754 0.875 0.834 0.798 0.765 0.735 0.708 8 0.707 9 0.666 10 0.632 11 0.602 0.576 0.553 12 0.684 13 0.661 0.641 0.623 0.606 14 0.532 0.514 15 16 17 0.497 0.482 0.468 0.456 0.444 0.590 0.575…
Suppose IQ scores were obtained for 20 randomly selected sets of siblings. The 20 pairs of measurements yield x = 99.37, y = 98.55, r=0.859, P-value = 0.000, and y = 10.94 +0.88x, where x represents the IQ score of the older child. Find the best predicted value of y given that the older child has an IQ of 105? Use a significance level of 0.05. 10CritPearson.pdf O A. 98.55 OB. 0.88 O C. 99.37 O D. 103.34
Is the proportion of wildfires caused by humans in the south higher than the proportion of wildfires caused by humans in the west? 367 of the 526 randomly selected wildfires looked at in the south were caused by humans while 390 of the 594 randomly selected wildfires looked at the west were caused by humans. What can be concluded at the a = 0.01 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: Select an answer > Select an answer > Select an answer O (please enter a decimal) H j: Select an answer Select an answer > Select an answer O (Please enter a decimal) c. The test statistic (please show = your answer to 3 decimal places.) d. The p-value (Please show your answer to %3D 4 decimal places.)
Find the standardized test statistic, z to test the claim that p, = p2. The sample statistics listed below are from independent samples. n1 = 50, x1 = 35, and n2 = 60, x2 = 40 ... О А. 1.328 В. 2.361 С. О.374 O D. 0.982
In a previous poll, 39% of adults with children under the age of 18 reported that their family ate dinner together seven nights a week. Suppose that, in a more recent poll, 422 of 1145 adults with children under the age of 18 reported that their family ate dinner together seven nights a week. Is there sufficient evidence that the proportion of families with children under the age of 18 who eat dinner together seven nights a week has decreased? Use the x = 0.01 significance level. Because npo (1-Po) = 272.4 > 10 and the sample size is the hypothesis are satisfied. (Round to one decimal place as needed.) What are the null and alternative hypotheses? Ho: P = versus H₁: ▼ V (Type integers or decimals. Do not round.) Find the test statistic, Zo- C less than 5% of the population size, and the sample is given to be random, the requirements for testing Zo = (Round to two decimal places as needed.) Find the P-value. P-value = (Round to three decimal places as needed.) Is there sufficient…
n 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 25 30 35 40 45 50 60 70 80 90 100 n x=0.05 0.950 0.878 0.811 0.754 0.707 0.666 0.632 0.602 0.576 0.553 0.532 0.514 0.497 0.482 0.468 0.456 0.444 0.396 0.361 0.335 0.312 0.294 0.279 0.254 0.236 0.220 0.207 0.196 α = 0.05 α = 0.01 0.990 0.959 0.917 0.875 0.834 0.798 0.765 0.735 0.708 0.684 0.661 0.641 0.623 0.606 0.590 0.575 0.561 0.505 0.463 0.430 0.402 0.378 0.361 0.330 0.305 0.286 0.269 0.256 α = 0.01 NOTE: To test Ho: p=0 against H₁: p0, reject Ho if the absolute value of ris greater than the critical value in the table.
Consider two sets of data, X and Y, with n = 10 observations each. If the mean ranks for X and Y are 6 and 5, respectively, what is the test statistic for the Wilcoxon Signed-Ranks test on these two sets of data?
The Substance Abuse and Mental Health Services Administration (SAMHSA, 2017) estimates that 10.9% of the population of the United States age 18–24 had an episode of depression in the previous 12 months. Suppose a researcher takes a random sample of 225 United States adults aged 18–24. Determine the value of the sample proportion, p, such that 5% of samples of 225 United States adults age 18–24 are greater than p. You may find software or a z-table useful. Give your answer precise to three decimal places. p = II
Katie is interested if an association exists between age and sleep habits. She selects a random sample of 68 adults in three age groups and determines whether they sleep less than 7 hours, between 7 and 8 hours, or more than 8 hours each night. She would like to determine if there is convincing evidence of an association. Let = 0.05. What are the hypotheses for this test? H0: There is an association between age and sleep habits.Ha: There is no association between age and sleep habits. H0: There is no association between age and sleep habits.Ha: There is an association between age and sleep habits. H0: There is no difference in the distribution of age and sleep habits.Ha: There is a difference in the distribution of age and sleep habits. H0: There is a difference in the distribution of age and sleep habits.Ha: There is no difference in the distribution of age and sleep habits.

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