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- What is the test statistic? What is the p-value? Can we conclude that the mean travel times of the two routes are different? Yes or No?Two popular brands of tires for tractor-trailers are the Puma and the Eternal. Salma is a buyer for a major shipping company and wants to determine if there is any difference between the two brands of tire in the mean distance (in thousands of km) driven on them before they need to be replaced. In the company's testing lab, Salma tests a random sample of 14 Puma tires and a random sample of 15 Eternal tires. (These samples are chosen independently.) For the Puma tires, the sample mean distance (in thousands of km) until they would need to be replaced is 54.71 with a sample variance of 5.95. For the Eternal tires, the sample mean distance (in km) until they would need to be replaced is 50.21 with a sample variance of 37.75. Assume that the two populations of distances driven are approximately normally distributed. Can Salma conclude, at the 0.05 level of significance, that there is a difference between the population mean of the distances (in thousands of km) driven on Puma tires before…An adventure company runs two obstacle courses, Fundash and Coolsprint. The designer of the courses suspects that the mean completion time of Fundash is not equal to the mean completion time of Coolsprint. To test this, she selects 205 Fundash runners and 300 Coolsprint runners. (Consider these as random samples of the Fundash and Coolspring runners.) The 205 Fundash runners complete the course with a mean time of 76.7 minutes and a standard deviation of 5.3 minutes. The 300 Coolsprint runners complete the course with a mean time of 77.5 minutes and a standard deviation of 5.1 minutes. Assume that the population standard deviations of the completion times can be estimated to be the sample standard deviations, since the samples that are used to compute them are quite large. At the 0.05 level of significance, is there enough evidence to support the claim that the mean completion time, ,, of Fundash is not equal to the mean completion time, μ₂, of Coolsprint? Perform a two-tailed test.…
- The College Board provided comparisons of Scholastic Aptitude Test (SAT) scores based on the highest level of education attained by the test taker's parents. A research hypothesis was that students whose parents had attained a higher level of education would on average score higher on the SAT. The overall mean SAT math score was 514. SAT math scores for independent samples of students follow. The first sample shows the SAT math test scores for students whose parents are college graduates with a bachelor's degree. The second sample shows the SAT math test scores for students whose parents are high school graduates but do not have a college degree. College Grads 485 487 518 517 650 542 570 426 566 499 588 562 497 448 592 453 High School Grads 442 492 580 478 479 425 486 485 528 390 524 535 (b) What is the point estimate of the difference between the means for the two populations? (c) Find the value of the test statistic. (Round your answer…An adventure company runs two obstacle courses, Fundash and Coolsprint. The designer of the courses suspects that the mean completion time of Fundash is not equal to the mean completion time of Coolsprint. To test this, she selects 250 Fundash runners and 285 Coolsprint runners. (Consider these as random samples of the Fundash and Coolspring runners.) The 250 Fundash runners complete the course with a mean time of 76.7 minutes and a standard deviation of 5.7 minutes. The 285 Coolsprint runners complete the course with a mean time of 77.5 minutes and a standard deviation of 5.6 minutes. Assume that the population standard deviations of the completion times can be estimated to be the sample standard deviations, since the samples that are used to compute them are quite large. At the 0.05 level of significance, is there enough evidence to support the claim that the mean completion time, u, of Fundash is not equal to the mean completion time, µa, of Coolsprint? Perform a two-tailed test.…In a population of 150 pea plants, there are 89 tall-purple plants, 25 short-purple plants, 28 tall-white plants, and 8 short-white plants. In order to test if the two traits are experiencing independent assortment researchers would perform a chi squared test. What is your calculated Chi Squared statistic? What is the corresponding P value?
- Is the proportion of wildfires caused by humans in the south different from the proportion of wildfires caused by humans in the west? 350 of the 519 randomly selected wildfires looked at in the south were caused by humans while 383 of the 500 randomly selected wildfires looked at the west were caused by humans. What can be concluded at the a = 0.01 level of significance? Rectangular Snip a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: Select an answer | (please enter a decimal) Select an answer v Select an answer H1: Select an answer v Select an answer vSelect an answer v (Please enter a decimal) c. The test statistic ? v = (please show your answer to 3 decimal places.)Is the proportion of wildfires caused by humans in the south higher than the proportion of wildfires caused by humans in the west? 380 of the 581 randomly selected wildfires looked at in the south were caused by humans while 318 of the 503 randomly selected wildfires looked at the west were caused by humans. What can be concluded at the a = 0.10 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: Select an answer v Select an answer Select an answer v (please enter a decimal) Hj: Select an answer Select an answer vSelect an answer v (Please enter a decimal) c. The test statistic ? v (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? a f. Based on this, we should Select an answer g. Thus, the final conclusion is that ... |the null hypothesis. O The results are statistically significant at a = 0.10, so there is sufficient evidence to…Is the proportion of wildfires caused by humans in the south higher than the proportion of wildfires caused by humans in the west? 348 of the 574 randomly selected wildfires looked at in the south were caused by humans while 272 of the 518 randomly selected wildfires looked at the west were caused by humans. What can be concluded at the = 0.01 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: Select an answer Select an answer Select an answer (please enter a decimal) H₁: Select an answer Select an answer Select an answer (Please enter a decimal) = c. The test statistic ? ◊ your answer to 3 decimal places.) (please show
- According to the Humane Society, 33% of households in the United States own at least one cat. You are interested in determining whether the proportion of households of the students at your school that own at least one cat is different from the national proportion. Suppose you survey an SRS of students at your school and find that 25% of them own cats, which yields a p-value of .092. Interpret this p-value.Many people like to play app based games on their mobile devices. Suppose we would like to estimate the average amount of time (in hours) per week students have played an app-based game on their mobile device at CSU Stan. In order to do this, we take a random sample of 20 students and ask them how many hours they have played an app- based game in the last week. The following data were collected: 11 4 5.5 5.5 7 6.2 10 10 7.5 6 7 7.5 2.5 Which of the following is the correct 99% confidence interval for the estimate of the average number of hours (per week) that all CSU Stan students have played an app- based game? [5.28, 7.59] [4.86, 8.01] [5.48,7.39] [5.86, 7.01]According to previous studies, the mean distance each visitor in Greenspan National Park hikes during their visit is 30 kilometers. The park recently closed its shuttle system, which used to transport hikers to many of the park's most popular hiking trails. Because of this, an administrator at the park suspects the mean distance, u, is now less than 30 kilometers. The administrator chooses a random sample of 45 visitors. The mean distance hiked for the sample is 27.2 kilometers. Assume the population standard deviation is 9.9 kilometers. Can the administrator conclude that the mean distance hiked by each visitor is now less than 30 kilometers? Perform a hypothesis test, using the 0.10 level of significance. (a) State the null hypothesis H, and the alternative hYpothesis H,. OSEE MORE QUESTIONS