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- A school district decided to measure the BMI of all 3rd graders and identify the highest 1% and lowest 1% of those students, and those students will be included in a follow up program. If Abby's BMI is converted to a z score of -2.18, would she be included in the program?It’s assumed that students need to stay awake more to study during finals week. One way to measure this is how much coffee is consumed during Finals week at night. A local coffee house near APU counted the number of cups of coffee sold per hour during Finals week after 6 p.m. We randomly select ten (10) hours of sales records during Finals week and find out that the following number of cups of coffee were consumed: 18, 17, 22, 14, 17, 20, 22, 24, 15, 15 By comparison, the sales records from a previous week were used as a comparison. The following number of cups of coffee were consumed over a seven (7) hour period: 9, 13, 5, 15, 17, 10, 11 a. Determine what is the appropriate statistical procedure, with a brief explanation (one sentence) as to why this is the appropriate procedure. b. State the null hypothesis. c. Execute the proper calculations with the appropriate procedures. d. Present a graph when appropriate of your results. e. Include any appropriate post-hoc tests. f. State…An adventure company runs two obstacle courses, Fundash and Coolsprint. The designer of the courses suspects that the mean completion time of Fundash is not equal to the mean completion time of Coolsprint. To test this, she selects 250 Fundash runners and 285 Coolsprint runners. (Consider these as random samples of the Fundash and Coolspring runners.) The 250 Fundash runners complete the course with a mean time of 76.7 minutes and a standard deviation of 5.7 minutes. The 285 Coolsprint runners complete the course with a mean time of 77.5 minutes and a standard deviation of 5.6 minutes. Assume that the population standard deviations of the completion times can be estimated to be the sample standard deviations, since the samples that are used to compute them are quite large. At the 0.05 level of significance, is there enough evidence to support the claim that the mean completion time, u, of Fundash is not equal to the mean completion time, µa, of Coolsprint? Perform a two-tailed test.…
- A car wash is assessing the average wait time for its customers. The median wait time is 4 minutes. Does a customer who waits for 5 minutes represent an abnormal wait time? The customer who waits 5 minutes an abnormal case, because 50% of customers wait more than minutes.A doctor in Oklahoma City wants to know whether the average life span for heart disease patients at four hospitals in the city differ. The data below represents the life span, in years, of heart disease patients from each hospital. Perform an ANOVA test with a 10% level of significance to test whether the average life span of heart disease patients in Oklahoma City differs depending on the hospital that treats them Life Span of Patients Treated at Hospital 1: 8.1, 1.2, 7, 11.5, 21, 2, 15.3, 19.2, 10.5, 15.4, 12.7, 15.3, 12.1, 7.5, 11.4, 16.4, 26.7, 14.6, 1.5, 16.3, 12.6, 0.8, 18.2, 4.2, 9.6, 21, 16.3, 2.7 Life Span of Patients Treated at Hospital 2: 17.6, 11.6, 16.8, 5.2, 6.7, 3.2, 13.8, 12.5, 0.9, 6, 14.3, 1.8, 14.8, 10, 5.8, 15.2, 10, 3.7, 11.4, 21.6, 12.9, 0.5, 9.2, 13.9, 10.9 ▼ Part 1 of 4 Life Span of Patients Treated at Hospital 3: 8.5, 2.3, 11, 7.4, 14.8, 5.8, 11, 3.4, 10.9, 1.1, 5.9, 21.6, 12.5, 0.1, 15.5, 15.4, 0.8, 7.7, 5.6, 12, 7.1 Life Span of Patients Treated at Hospital…GMU uses a robot food delivery service which now has been utilized in the City of Fairfax. One of the potential benefits of this service is to help the busiest students eat breakfast. Research has shown that about 80% of college students skip breakfast due to busy schedules and other reasons. Initial data were collected from a random sample of 595 Mason students who utilize the robot food delivery service and are presented in StatCrunch. Show the full calculation of the sample proportion by including the number of students who skipped breakfast, the total number of students sampled, and the value of the sample proportion. Present this sample proportion as a decimal rounded to four decimal places. Frequency table results for Breakfast?Count = 595 Breakfast? Frequency Relative Frequency 0 142 0.23865546 1 453 0.76134454
- A nationwide job recruiting firm wants to compare the annual incomes for childcare workers in New York and Illinois. Due to recent trends in the childcare industry, the firm suspects that the that the mean annual income of childcare workers in the state of New York is greater than the mean annual income of childcare workers in Illinois. To see if this is true, the firm selected a random sample of 15 childcare workers from New York and an independent random sample of 15 childcare workers from Illinois and asked them to report their mean annual income. The data obtained were as follows. Annual income in dollars New York 49378, 44459, 50396, 48428, 53720, 60711, 50900, 49846, 57630, 49813, 52923, 60662, 50060, 45923, 45433 Illinois 47959, 51289, 46467, 42758, 46502, 48032, 40452, 40702, 45428, 33593, 44348, 45763, 54745, 46015, 37396 Send data to calculator Send data to Excel The population standard deviations for the annual incomes of childcare workers in New York and in Illinois are…An adventure company runs two obstacle courses, Fundash and Coolsprint. The designer of the courses suspects that the mean completion time of Fundash is not equal to the mean completion time of Coolsprint. To test this, she selects 240 Fundash runners and 200 Coolsprint runners. (Consider these as random samples of the Fundash and Coolspring runners.) The 240 Fundash runners complete the course with a mean time of 76.7 minutes and a standard deviation of 5.2 minutes. The 200 Coolsprint runners complete the course with a mean time of 77.5 minutes and a standard deviation of 5.4 minutes. Assume that the population standard deviations of the completion times can be estimated to be the sample standard deviations, since the samples that are used to compute them are quite large. At the 0.05 level of significance, is there enough evidence to support the claim that the mean completion time, μ1 , of Fundash is not equal to the mean completion time, μ2 , of Coolsprint?…The American Water Works Association reports that, The average household water usage is more than 10 gallons per day. However, in a pandemic like this, it is suspected that there is a change in household water consumption. A researcher conducted a survey and took samples of 12 household heads and asked about the use of the gallon water. The data obtained are as follows: 74, 8, 13, 17, 13, 15, 12, 13, 15, 16, 9, 7. If it is known that the data is normally distributed. Use a significance level of 5% to test whether the average household water use has increased (greater than 10 gallons)? What will happen if the household's water use increases by 5% from the previous one? Analyze your answer and come up with a conclusion!
- A nationwide job recruiting firm wants to compare the annual incomes for childcare workers in Connecticut and California. Due to recent trends in the childcare industry, the firm suspects that the that the mean annual income of childcare workers in the state of Connecticut is greater than the mean annual income of childcare workers in California. To see if this is true, the firm selected a random sample of 10 childcare workers from Connecticut and an independent random sample of 10 childcare workers from California and asked them to report their mean annual income. The data obtained were as follows. 80°F Partly sunny Annual income in dollars Connecticut 42438, 52287, 46837, 49334, 52848, 52929, 57111, 51860, 44967, 52174 California 50998, 38334, 56804, 50919, 49446, 41141, 45717, 43963, 55156, 47295 LL D 144Hz Send data to calculator V The population standard deviations for the annual incomes of childcare workers in Connecticut and in California are estimated as 6300 and 6100,…A nationwide job recruiting firm wants to compare the annual incomes for childcare workers in New York and Illinois. Due to recent trends in the childcare industry, the firm suspects that the that the mean annual income of childcare workers in the state of New York is greater than the mean annual income of childcare workers in Illinois. To see if this is true, the firm selected a random sample of 15 childcare workers from New York and an independent random sample of 15 childcare workers from Illinois and asked them to report their mean annual income. The data obtained were as follows. Annual income in dollars New York 44965, 34979. 54554, 45692. 52228, 54340, 56915, 42473, 46109. 37384, 50108, 47627, 42682, 52168, 61923 Illinois 34604. 50975, 39437, 47344, 40911, 48065, 31985, 33064, 50130. 49985, 47805, 51873, 42676. 47858, 40965| Send data to calculator Send data to Excel The population standard deviations for the annual incomes of childcare workers in New York and in Illinois are…