Example ProblemThe fluid being pumped is oil with a specific gravity of 0.86. Calculate the energy delivered by the pump to theoil per unit weight of oil flowing in the system. Energy losses in the system are caused by check valve andfriction losses as the fluid flows through the piping. The magnitude of such losses has been determined to be1.86 N.m/N.Pump system. The volume flow rate through the pump shown in figure below is 0.014 m³/s.SOLUTION:+EOPB = 296 kPaSchedule 40 (From Pipe Supplier's Table)WallFlow AreaaoNOaoThicknessDN 50 Schedule 40(ww)0.002163steel pipe60.33.9152.4888.9 5.4977.920.00476808GENERAL ENERGY EQUATION BETWEEN POINTS A & B:FlowPA/y + Z, + v/2g +h- hg -h = PB/y+ ZB + Vp²/2g1.0 m%3DTherefore,Ty + 87/(A -A) + ("z - "z ) + ^/(°d - d) = 'yDN 80 Schedule 40%3DCheck valveFrom continuityequation, v = Q/A,find VA & VBVA = ?steel pipePA =-28 kPa%3DVs = ?PumpCHECK ANSWERh =42.9 m, or 42.9 N.m/N%3D5.

Name: Example ProblemThe fluid being pumped is oil with a specific gravity
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Description: Example ProblemThe fluid being pumped is oil with a specific gravity of 0.86. Calculate the energy delivered by the pump to theoil per unit weight of oil flowing in the system. Energy losses in the system are caused by check valve andfriction losses

Given data Volumetric flow rate (Q) = 0.014 m3/s sg = 0.86 flow area for DN 80 schedule 80 (Aa) =…

Engineering

Mechanical Engineering

Example Problem The fluid being pumped is oil with a specific gravity of 0.86. Calculate the energy delivered by the pump to the oil per unit weight of oil flowing in the system. Energy losses in the system are caused by check valve and friction losses as the fluid flows through the piping. The magnitude of such losses has been determined to be 1.86 N.m/N. Pump system. The volume flow rate through the pump shown in figure below is 0.014 m³/s. SOLUTION: B. PB=296 kPa %3D Schedule 40 (From Pipe Supplier's Table) Wall aI Flow Area NO ao Thickness DN 50 Schedule 40 (ww) 52.48 (ww) 0.002163 steel pipe 60.3 3.91 88.9 5.49 77.92 0.004768 GENERAL ENERGY EQUATION BETWEEN POINTS A & B: Flow PA/y + Z, + va?/2g +h, - hg - h = Pg/y+ Zg + VB²/2g 1.0 m %3D Therefore, Tụ + 87/(¿YA - "^) + ('z - "z ) + ^/(°d - d) = 'y DN 80 Schedule 40 %3D Check valve From continuity VA =? steel pipe equation, v = Q/A, %3D PA=-28 kPa V8 = ? Pump CHECK ANSWER = 42.9 m, or 42.9 N.m/N

Example Problem The fluid being pumped is oil with a specific gravity of 0.86. Calculate the energy delivered by the pump to the oil per unit weight of oil flowing in the system. Energy losses in the system are caused by check valve and friction losses as the fluid flows through the piping. The magnitude of such losses has been determined to be 1.86 N.m/N. Pump system. The volume flow rate through the pump shown in figure below is 0.014 m³/s. SOLUTION: B. PB=296 kPa %3D Schedule 40 (From Pipe Supplier's Table) Wall aI Flow Area NO ao Thickness DN 50 Schedule 40 (ww) 52.48 (ww) 0.002163 steel pipe 60.3 3.91 88.9 5.49 77.92 0.004768 GENERAL ENERGY EQUATION BETWEEN POINTS A & B: Flow PA/y + Z, + va?/2g +h, - hg - h = Pg/y+ Zg + VB²/2g 1.0 m %3D Therefore, Tụ + 87/(¿YA - "^) + ('z - "z ) + ^/(°d - d) = 'y DN 80 Schedule 40 %3D Check valve From continuity VA =? steel pipe equation, v = Q/A, %3D PA=-28 kPa V8 = ? Pump CHECK ANSWER = 42.9 m, or 42.9 N.m/N

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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