Example Problem The fluid being pumped is oil with a specific gravity of 0.86. Calculate the energy delivered by the pump to the oil per unit weight of oil flowing in the system. Energy losses in the system are caused by check valve and friction losses as the fluid flows through the piping. The magnitude of such losses has been determined to be 1.86 N.m/N. Pump system. The volume flow rate through the pump shown in figure below is 0.014 m³/s. SOLUTION: B. PB=296 kPa %3D Schedule 40 (From Pipe Supplier's Table) Wall aI Flow Area NO ao Thickness DN 50 Schedule 40 (ww) 52.48 (ww) 0.002163 steel pipe 60.3 3.91 88.9 5.49 77.92 0.004768 GENERAL ENERGY EQUATION BETWEEN POINTS A & B: Flow PA/y + Z, + va?/2g +h, - hg - h = Pg/y+ Zg + VB²/2g 1.0 m %3D Therefore, Tụ + 87/(¿YA - "^) + ('z - "z ) + ^/(°d - d) = 'y DN 80 Schedule 40 %3D Check valve From continuity VA =? steel pipe equation, v = Q/A, %3D PA=-28 kPa V8 = ? Pump CHECK ANSWER = 42.9 m, or 42.9 N.m/N

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
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Example Problem
The fluid being pumped is oil with a specific gravity of 0.86. Calculate the energy delivered by the pump to the
oil per unit weight of oil flowing in the system. Energy losses in the system are caused by check valve and
friction losses as the fluid flows through the piping. The magnitude of such losses has been determined to be
1.86 N.m/N.
Pump system. The volume flow rate through the pump shown in figure below is 0.014 m³/s.
SOLUTION:
+EO
PB = 296 kPa
Schedule 40 (From Pipe Supplier's Table)
Wall
Flow Area
ao
NO
ao
Thickness
DN 50 Schedule 40
(ww)
0.002163
steel pipe
60.3
3.91
52.48
88.9 5.49
77.92
0.004768
08
GENERAL ENERGY EQUATION BETWEEN POINTS A & B:
Flow
PA/y + Z, + v/2g +h- hg -h = PB/y+ ZB + Vp²/2g
1.0 m
%3D
Therefore,
Ty + 87/(A -A) + ("z - "z ) + ^/(°d - d) = 'y
DN 80 Schedule 40
%3D
Check valve
From continuity
equation, v = Q/A,
find VA & VB
VA = ?
steel pipe
PA =-28 kPa
%3D
Vs = ?
Pump
CHECK ANSWER
h =42.9 m, or 42.9 N.m/N
%3D
5.
Transcribed Image Text:Example Problem The fluid being pumped is oil with a specific gravity of 0.86. Calculate the energy delivered by the pump to the oil per unit weight of oil flowing in the system. Energy losses in the system are caused by check valve and friction losses as the fluid flows through the piping. The magnitude of such losses has been determined to be 1.86 N.m/N. Pump system. The volume flow rate through the pump shown in figure below is 0.014 m³/s. SOLUTION: +EO PB = 296 kPa Schedule 40 (From Pipe Supplier's Table) Wall Flow Area ao NO ao Thickness DN 50 Schedule 40 (ww) 0.002163 steel pipe 60.3 3.91 52.48 88.9 5.49 77.92 0.004768 08 GENERAL ENERGY EQUATION BETWEEN POINTS A & B: Flow PA/y + Z, + v/2g +h- hg -h = PB/y+ ZB + Vp²/2g 1.0 m %3D Therefore, Ty + 87/(A -A) + ("z - "z ) + ^/(°d - d) = 'y DN 80 Schedule 40 %3D Check valve From continuity equation, v = Q/A, find VA & VB VA = ? steel pipe PA =-28 kPa %3D Vs = ? Pump CHECK ANSWER h =42.9 m, or 42.9 N.m/N %3D 5.
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