pressure relief valve has a pressure setting of 850 psi. Compute the horsepower loss across this valve if it returns all the flow back to the tank from a 180-gpm pump. An unloading valve is used instead to unload the pump. If the pump discharge pressure during unloading quals 50 psi, how much hydraulic horsepower is being wasted?
pressure relief valve has a pressure setting of 850 psi. Compute the horsepower loss across this valve if it returns all the flow back to the tank from a 180-gpm pump. An unloading valve is used instead to unload the pump. If the pump discharge pressure during unloading quals 50 psi, how much hydraulic horsepower is being wasted?
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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![### Hydraulic System Efficiency Analysis
#### Problem Statement
A pressure relief valve has a pressure setting of 850 psi. Compute the horsepower loss across this valve if it returns all the flow back to the tank from a 180-gpm pump. An unloading valve is used instead to unload the pump. If the pump discharge pressure during unloading equals 50 psi, how much hydraulic horsepower is being wasted?
#### Explanation of Terms:
- **Pressure Relief Valve**: A valve that releases pressure to prevent damage to the system.
- **Gallons Per Minute (gpm)**: A unit of volumetric flow rate.
- **Pressure Setting (psi)**: Pounds per square inch, a measure of pressure.
- **Horsepower (HP)**: A unit of power.
To solve the problem, use the formula for hydraulic power:
\[ \text{Power} \, (HP) = \frac{\text{Flow} \, (gpm) \times \text{Pressure} \, (psi)}{1714} \]
1. **Total Horsepower Input with Relief Valve**:
- Pressure setting: 850 psi
- Flow rate: 180 gpm
\[ \text{HP}_{\text{relief}} = \frac{180 \times 850}{1714} \approx 89.17 \text{ HP} \]
2. **Horsepower Input with Unloading Valve**:
- Pressure setting: 50 psi
- Flow rate: 180 gpm
\[ \text{HP}_{\text{unload}} = \frac{180 \times 50}{1714} \approx 5.25 \text{ HP} \]
3. **Hydraulic Horsepower Wasted**:
\[ \text{HP}_{\text{wasted}} = 89.17 - 5.25 \approx 83.92 \text{ HP} \]
Thus, the hydraulic horsepower being wasted is approximately **83.92 HP**.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6a2e60b5-531b-408d-ad87-91178dbcae31%2F3fce6887-01c8-4b31-9826-e5aa39ed3da6%2F4b1afpt_processed.gif&w=3840&q=75)
Transcribed Image Text:### Hydraulic System Efficiency Analysis
#### Problem Statement
A pressure relief valve has a pressure setting of 850 psi. Compute the horsepower loss across this valve if it returns all the flow back to the tank from a 180-gpm pump. An unloading valve is used instead to unload the pump. If the pump discharge pressure during unloading equals 50 psi, how much hydraulic horsepower is being wasted?
#### Explanation of Terms:
- **Pressure Relief Valve**: A valve that releases pressure to prevent damage to the system.
- **Gallons Per Minute (gpm)**: A unit of volumetric flow rate.
- **Pressure Setting (psi)**: Pounds per square inch, a measure of pressure.
- **Horsepower (HP)**: A unit of power.
To solve the problem, use the formula for hydraulic power:
\[ \text{Power} \, (HP) = \frac{\text{Flow} \, (gpm) \times \text{Pressure} \, (psi)}{1714} \]
1. **Total Horsepower Input with Relief Valve**:
- Pressure setting: 850 psi
- Flow rate: 180 gpm
\[ \text{HP}_{\text{relief}} = \frac{180 \times 850}{1714} \approx 89.17 \text{ HP} \]
2. **Horsepower Input with Unloading Valve**:
- Pressure setting: 50 psi
- Flow rate: 180 gpm
\[ \text{HP}_{\text{unload}} = \frac{180 \times 50}{1714} \approx 5.25 \text{ HP} \]
3. **Hydraulic Horsepower Wasted**:
\[ \text{HP}_{\text{wasted}} = 89.17 - 5.25 \approx 83.92 \text{ HP} \]
Thus, the hydraulic horsepower being wasted is approximately **83.92 HP**.
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