Example:Design a new flexible pavement for a major interstate highway using thefollowing conditions:Pavement location : RuralNumber of lanes :2 lanes in each directionTotal traffic during peak hour : 267 ESALDesign period : 16 yearsGrowth factor : 12%Traffic distribution design of lane factor Lf: 65%Sub-grade CBR : 8%Standard deviation : 40%Overall serviceability loss: Po - Pt 4.2 -2 = 2.2Solution:Step 1:Reliability (R) = 90% , Rural (Table 8.5)Step 2:Standard deviation (So) = 40% (Given)Step 3:Cumulative expected ESAL during design life in the design lane (W18)W18 = ADT x 365 x G x Df x LfADT = (Total traffic during peak hour) x 24= 267 x 24 = 6408 EASL(1+i)"f-1(1+0.12)16-1G == 45.613i0.1222Df = 0.93 2 lanes each direction (Table 8.6)W18 = 6408 x 365 x 45.613 x 0.93 x 0.65= 64491246 x 64 x 106 ESALD1 = ?D2 = ?D3 = ?

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Example: Design a new flexible pavement for a major interstate highway using the following conditions: Pavement location : Rural Number of lanes :2 lanes in each direction Total traffic during peak hour : 267 ESAL Design period : 16 years Growth factor : 12% Traffic distribution design of lane factor Lf: 65% Sub-grade CBR : 8% Standard deviation : 40% Overall serviceability loss: Po - Pt = 4.2 -2 = 2.2

Example: Design a new flexible pavement for a major interstate highway using the following conditions: Pavement location : Rural Number of lanes :2 lanes in each direction Total traffic during peak hour : 267 ESAL Design period : 16 years Growth factor : 12% Traffic distribution design of lane factor Lf: 65% Sub-grade CBR : 8% Standard deviation : 40% Overall serviceability loss: Po - Pt = 4.2 -2 = 2.2

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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