Example 9 A copper surface area, A=100 cm², is exposed to an acid solution. After 24 hour, the loss of copper due to corrosion (Oxidation) is 15*10* gram. Calculate: (a) The current density in µA/cm². (b) The corrosion rate in mm/y Given that: molar mass for copper = 63.54 g/mc p = 8.96 g/cm
Example 9 A copper surface area, A=100 cm², is exposed to an acid solution. After 24 hour, the loss of copper due to corrosion (Oxidation) is 15*10* gram. Calculate: (a) The current density in µA/cm². (b) The corrosion rate in mm/y Given that: molar mass for copper = 63.54 g/mc p = 8.96 g/cm
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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![Example 9
A copper surface area , A=100 cm², is exposed to an acid solution. After 24 hour, the loss
of copper due to corrosion (Oxidation) is 15*10 gram. Calculate:
(a) The current density in µA/cm?.
(b) The corrosion rate in mm/y
Given that: molar mass for copper = 63.54 g/n
8.96 g/cm³](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3b828aa6-1054-4fc0-9308-7dc6e2786f55%2F888e3554-de38-48b0-98a4-4677fa28577e%2Fx5l5kx_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Example 9
A copper surface area , A=100 cm², is exposed to an acid solution. After 24 hour, the loss
of copper due to corrosion (Oxidation) is 15*10 gram. Calculate:
(a) The current density in µA/cm?.
(b) The corrosion rate in mm/y
Given that: molar mass for copper = 63.54 g/n
8.96 g/cm³
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