Example 9 A copper surface area, A=100 cm², is exposed to an acid solution. After 24 hour, the loss of copper due to corrosion (Oxidation) is 15*10* gram. Calculate: (a) The current density in µA/cm². (b) The corrosion rate in mm/y Given that: molar mass for copper = 63.54 g/mc p = 8.96 g/cm

Example 9 A copper surface area, A=100 cm², is exposed to an acid solution. After 24 hour, the loss of copper due to corrosion (Oxidation) is 1510 gram. Calculate: (a) The current density in µA/cm². (b) The corrosion rate in mm/y Given that: molar mass for copper = 63.54 g/mc p = 8.96 g/cm

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Example 9
A copper surface area , A=100 cm², is exposed to an acid solution. After 24 hour, the loss
of copper due to corrosion (Oxidation) is 15*10 gram. Calculate:
(a) The current density in µA/cm?.
(b) The corrosion rate in mm/y
Given that: molar mass for copper = 63.54 g/n
8.96 g/cm³

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