7. Solutions A and B are separated by a membrane that is permeable to Ca²+ and impermeable to Cl¯. Solution A contains 10 mM CaCl2, and solution B contains 1 mM CaCl₂. Assuming that 2.3 RT/F 60 mV, Ca²+ will be at electrochemical equilibrium when = (A) solution A is +60 mV (B) solution A is +30 mV (C) solution A is -60 mV (D) solution A is -30 mV (E) solution A is +120 mV (F) solution A is -120 mV (G) the Ca²+ concentrations of the two solutions are equal
7. Solutions A and B are separated by a membrane that is permeable to Ca²+ and impermeable to Cl¯. Solution A contains 10 mM CaCl2, and solution B contains 1 mM CaCl₂. Assuming that 2.3 RT/F 60 mV, Ca²+ will be at electrochemical equilibrium when = (A) solution A is +60 mV (B) solution A is +30 mV (C) solution A is -60 mV (D) solution A is -30 mV (E) solution A is +120 mV (F) solution A is -120 mV (G) the Ca²+ concentrations of the two solutions are equal
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![7. Solutions A and B are separated by a membrane that is permeable to Ca²+
and impermeable to CI. Solution A contains 10 mM CaCl2, and solution B
contains 1 mM CaCl₂. Assuming that 2.3 RT/F = 60 mV, Ca²+ will be at
electrochemical equilibrium when
(A) solution A is +60 mV
(B) solution A is +30 mV
(C) solution A is -60 mV
(D) solution A is -30 mV
(E) solution A is +120 mV
(F) solution A is -120 mV
(G) the Ca²+ concentrations of the two solutions are equal](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F12c73aad-a588-4380-8774-2e7e48958bcc%2F22762d39-2cb5-41ff-954f-eb1f949421b3%2Fafrk9ol_processed.jpeg&w=3840&q=75)
Transcribed Image Text:7. Solutions A and B are separated by a membrane that is permeable to Ca²+
and impermeable to CI. Solution A contains 10 mM CaCl2, and solution B
contains 1 mM CaCl₂. Assuming that 2.3 RT/F = 60 mV, Ca²+ will be at
electrochemical equilibrium when
(A) solution A is +60 mV
(B) solution A is +30 mV
(C) solution A is -60 mV
(D) solution A is -30 mV
(E) solution A is +120 mV
(F) solution A is -120 mV
(G) the Ca²+ concentrations of the two solutions are equal
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