A current of 5.65×104 A is passed through an electrolysis cell containing molten KCl for 12.8 days. (a) How many grams of potassium are produced?  ____________g (b) How many liters of chlorine are collected, if the gas is at a temperature of 273 K and a pressure of 1.00 atm?  _____________L

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A current of 5.65×104 A is passed through an electrolysis cell containing molten KCl for 12.8 days.

(a) How many grams of potassium are produced?

 ____________g

(b) How many liters of chlorine are collected, if the gas is at a temperature of 273 K and a pressure of 1.00 atm?

 _____________L

Expert Solution
Step 1

The charge is calculated as,

Q = It

I: Current (A)

t: time (s)

Step 2

For KCl

1 mole of electron is required to reduce it from K+ to KQ = ItQ= 5.65 x 104 x 12.8 x 24 x 60 x 60Q = 6.24 x 1010 C

 

Step 3

1 mole of electron possess = 96500 C of chargeHence the number of moles of Potassium = 6.24 × 101096500Hence the number of moles of Potassium =646632.12 molesMass of potassium produced = 646632.12 x 39Mass of potassium produced = 25318652 grams

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